Negative acceleration
29 m/s
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
( 3 kg-m/sec2 ) x ( 5 sec ) = 15 kg-m/sec
2.666666667 seconds
432.25 m^3 However, if we're holding true to the margin of error, it is actually 432.2 m^3
m to the second power means multiply m by itself, or m x m.
[m][l]^-3
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
Negative acceleration
29 m/s
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
pencil
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
( 3 kg-m/sec2 ) x ( 5 sec ) = 15 kg-m/sec