A standard parking space is about 3 meters long.
When a constant force F is applied to an object with mass M, it will result in an acceleration of the object according to Newton's second law, F = ma, where F is the force, m is the mass of the object, and a is the acceleration. The object will continue to accelerate as long as the force is applied.
The object is undergoing deceleration, as its speed is decreasing from 10 m/s to 3 m/s. The acceleration is negative because it is in the opposite direction of its initial velocity.
Density is calculated by dividing the mass of an object by its volume. In this case, the density of the object would be 1250 kg/m^3 (500 kg / 0.4 m^3).
Density (d) is calculated by dividing the mass (m) of an object by its volume (V). The equation is: d = m/V. The unit of density is typically expressed in kg/m^3 or g/cm^3.
The magnitude of the force required to lift a 3-kilogram object straight upwards is equal to the object's weight, which is given by the formula F = m*g, where m is the mass of the object (3 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2). Therefore, the magnitude of the force is 29.4 Newtons.
2.666666667 seconds
432.25 m^3 However, if we're holding true to the margin of error, it is actually 432.2 m^3
m to the second power means multiply m by itself, or m x m.
When a constant force F is applied to an object with mass M, it will result in an acceleration of the object according to Newton's second law, F = ma, where F is the force, m is the mass of the object, and a is the acceleration. The object will continue to accelerate as long as the force is applied.
The object is undergoing deceleration, as its speed is decreasing from 10 m/s to 3 m/s. The acceleration is negative because it is in the opposite direction of its initial velocity.
Density is calculated by dividing the mass of an object by its volume. In this case, the density of the object would be 1250 kg/m^3 (500 kg / 0.4 m^3).
Density (d) is calculated by dividing the mass (m) of an object by its volume (V). The equation is: d = m/V. The unit of density is typically expressed in kg/m^3 or g/cm^3.
The magnitude of the force required to lift a 3-kilogram object straight upwards is equal to the object's weight, which is given by the formula F = m*g, where m is the mass of the object (3 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2). Therefore, the magnitude of the force is 29.4 Newtons.
The speed of the object after falling for 3 seconds in free fall is 29.4 m/s. This is because the acceleration due to gravity is about 9.8 m/s^2, so after 3 seconds the object would have reached a speed of 29.4 m/s.
The momentum of the object is calculated by multiplying its mass by its velocity. So, for an object with a mass of 3 kg moving at a velocity of 22 m/s, the momentum would be 66 kg*m/s.
Because the acceleration due to earth (gravitation) dose not depends on the mass of falling object & it's constant for deferent masses :F= (G M m) / d2 …(1)F = ma = mg ...(2)mg = (G M m) / d2g = (G M) / d2 …(3)Where F is The force of gravity , G is gravity constant , M is the mass of earth , m is the mass of the object , d is the distance between earth & the object , a is acceleration and g is gravitationfrom equation 3 since (G) and (M) are constant it's clear that (g) depends only on the distance (d) between Erath and the object and do not depend on the mass of falling object.
The object is undergoing deceleration with a constant rate of 3 m/s^2 in the opposite direction of its initial velocity. It is slowing down at a consistent rate of 3 m/s^2 each second.