The aluminum metal appears to be turning into copper, but it is actually just removing the metallic copper from its compound state. The Aluminum is oxidized and loses e-, becoming Al 3+ and the copper ions are reduced (they accept those e-) to form solid copper precipitate. The aluminum ions and chloride ions remain in the solution. The reaction will only occur in water and occurs because the transfer of electrons from the aluminum to the copper results in a more stable system.
the following reaction occurs:
2Al (s) + 3Cu2+ --> 2Al3+ + 3Cu (s)
The aluminum switches places with the copper in copper chloride. Aluminum is oxidized and loses e- and the copper ions are reduced (they accept those e-) to form solid copper precipitate.
When solid aluminum (Al) is placed into a solution of copper sulfate (CuSO4), the copper ions (Cu^2+) will become reduced to form solid copper (Cu) and the Al will be oxidized to aluminum ions (Al^3+). This is an oxidation reduction reaction and the half reactions can be written as:
Cu^2+(aq) + 2e- ===> Cu(s)
Al(s) ===> Al^3+ + 3e-
I've personally done this experiment, and although it looks like the aluminum is dissolving, the ionic bonds are breaking and causing the foil to decompose.
cu
It floats,
There is no reaction at all.
there is no chemical change when ammonium chloride is added to water. NH4Cl + H2O + heat -> products. it also cold when it is dissolved in water.
Temperature would increase
The gram atomic mass of aluminum is 26.9815; the gram atomic mass of chlorine is 35.453; and the formula of aluminum chloride is AlCl3, showing that three atoms of chlorine are required for each atom of aluminum in the compound. Therefore, mass ratio of chlorine to aluminum in the compound is [3 X (35.453])/26.9815 or 3.942. The ratio of reactant chlorine stated to be available to reactant aluminum stated to be available is 29.0/24.0 or 1.20, so that chlorine is clearly the limiting reactant. Therefore, the mass of aluminum in the maximum mass of aluminum chloride that can be made from the reactants stated is 29.0/3.942 or about 7.357 grams, and that added to the stated 29.0 g of chlorine constitutes 36.4 grams total of aluminum chloride, to the justified number of significant digits.
iodine and chloride ions
Please someone answer a question for CuSO4 + H2O+Al= What when added to Cupric Sulfate and Cupric Chloride? Need this for a science class!!
Ferric oxide (Fe2O3) is not soluble in water.
I think it turns from brown to a silver color
The reaction forms aluminum sulfate and frees copper.
Copper turnings react with HCl to form Copper chloride and give out hydrogen gas. Cu(s) + 2HCl -----> CuCl2 +H2(g)
when aluminium is added to dil. hcl it forms aluminium chloride and hydrogen gas. 4 Al + +6 HCL=2 Al2CO3 + 3 H2
Nothing
Silver chloride is not soluble in water.
silver chloride should precipitate out.
When you mix the solutions of Sodium Hydroxide and barium chloride then a double replecement occurs.2 NaOH + BaCl2 = 2 NaCl + Ba(OH)2
Sodium chloride is easily dissolved.
There is no reaction at all.