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The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
What you want is a pendulum with a frequency of 1/2 Hz. It swings left for 1 second,then right for 1 second, ticks once in each direction, and completes its cycle in exactly2 seconds.The length of such a pendulum technically depends on the acceleration due to gravityin the place where it's swinging. In fact, pendulum arrangements are used to measurethe local value of gravity.A good representative value for the length of the "seconds pendulum" is 0.994 meter.
It is assumed that the question asks "for the same period". The period of a simple pendulum, for "very short swings", is 2 pi (L/G)0.5. Since G on the moon is 0.165 that of Earth, L would have to be 0.165, so that 1 m pendulum would have to be about 0.165 m long in order to give the same swing period.
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.
For a simple pendulum: Period = 6.3437 (rounded) seconds
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
Making the length of the pendulum longer. Also, reducing gravitation (that is, using the pendulum on a low-gravity world would also increase the period).
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
You mean the length? We can derive an expression for the period of oscillation as T = 2pi ./(l/g) Here l is the length of the pendulum. So as length is increased by 4 times then the period would increase by 2 times.
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
It doesn't matter what unit you use to measure the physical length of the pendulum. As a matter of fact, it doesn't matter what unit you use to measure the duration of its period either. If both are at rest on the same planet, then the penduum with the longer string has the longer period. Period!
It would tend towards infinity
A longer pendulum will result in a longer period. The clock would go slower.
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2