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The answer depends on 3240 WHAT: seconds, days, years?
because
try using my formula.... ar=a(1/2)^2t therefore, 57(.05) = 57(1/2)^2t and 57s cancels out, .05 = 1/2^2t log .05 = log .5^2t divide log .5 from both sides, 4.32 = 2t t = 2.16, therefore 126 seconds or 2 minutes and 6 seconds
parameter !
Select the sample so that it will have the same percentages of people that are men and women as are in the system, and also match the percentage based on educational background and ethnicity
1.5% remains after 43.2 seconds.
This fraction is 12,5 %.
2
75
1/32
By definition, 50%. Half life is the time for half of the original sample to decay.
An eighth remains.
It tells what fraction of a radioactive sample remains after a certain length of time.
The fraction that remains is 1/8.
After 1.6 seconds, 0.6 g astatine-218 remains unchanged. This amount is reduced by half to 0.3 g at 3.2 seconds. It is halved again at 4.8 seconds to 0.15 g, and halved once more to 0.075 g unchanged after a total of 6.4 seconds.
1/8 of the original amount remains.
In reality, as the atoms gets decayed it gives out radiations such as alpha, beta and Gama. Alpha is a helium nucleus which is massive and beta is electron but fast moving and Gama is an electromagnetic radiation. So as the atom decays then its mass is likely to be reduced. Rutherford's radioactive law deals with the number of atoms undecayed present at an instant 't' given in the form N = No e-lambda t Here No is the total atoms present both decayed and undecayed in a sample. N is the number undecayed present lambda - the decay constant t - the time elapsed