There is no water in sulfur; sulfur is an element and therefore does not contain any other chemical substance.
Interesting question, since sulfur will not dissolve or react with water. But if it did, one gallon of a 1/2% (by weight) solution of "sulfur water" would weigh 8.3817 pounds. (There would be about 2/3rds of an ounce of sulfur "dissolved" in the water.)
The percent by mass of sulfur in a sulfur oxide compound can vary depending on the specific compound. For example, in sulfur dioxide (SO2), which contains one sulfur atom and two oxygen atoms, the percent by mass of sulfur would be approximately 50%. In sulfur trioxide (SO3), which contains one sulfur atom and three oxygen atoms, the percent by mass of sulfur would be approximately 40%.
Sulfur dioxide (SO2) is composed of one sulfur atom and two oxygen atoms. To calculate the percent sulfur, divide the atomic mass of sulfur by the molecular mass of sulfur dioxide, then multiply by 100. The percent sulfur in sulfur dioxide is approximately 50%.
it so very easy you can answer that joke the answer is percent of sulfur in ammonium sulfate
The molar mass of sulfur dioxide (SO2) is 64.06 g/mol. The molar mass of sulfur is 32.06 g/mol. Calculate the mass percent of sulfur in SO2 using the formula (mass of sulfur / mass of SO2) x 100%. This gives a mass percent of sulfur in SO2 as 50%.
Sulfur trioxide (SO3) contains about 40% sulfur by mass.
H2S2O8 has a larger percent by mass of sulfur because it contains two sulfur atoms in each molecule compared to one sulfur atom in H2SO3.
The formula of the compound between calcium and sulfur with the given percent composition would be CaS. This is because the ratio of calcium to sulfur atoms in calcium sulfide matches the given percentage composition.
21.95%
Jupiter's atmosphere is 90 percent hydrogen and 10 percent helium. There are also some small amounts of sulfur, ammonia, water vapor and methane.
h2s2o3 has the largest because it has more sulfur
The percent composition of sulfur in a compound is calculated by dividing the mass of sulfur by the total mass of the compound and then multiplying by 100. For example, in sulfuric acid (H2SO4), since the molar mass of sulfur is 32 g/mol and the total molar mass of sulfuric acid is 98 g/mol, the percent composition of sulfur would be (32/98) x 100 = 32.65%.