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An electron, being a charged body, is acted on by a force, and is therefore

accelerated, when immersed in an electric field. If you really want to be cruel,

you attach numbers to the whole situation and hand it to someone to solve.

The kinetic energy of a moving electron is

KE = (Lorentz factor - 1) x (rest-masselectron) x c2

Lorentz factor = [sqrt( 1 - v2/c2 )]-1

KE107 m/s = (4.5588 x 10-17 Joule) / (1.6 x 10-19 eV/J ) = 284.9 electron-volts

So you need 285 volts between the plates in order to have the electrons moving

as fast as you want them when they hit the positive plate.

I'm sure there had to be an easier way to do this.

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Q: What potential difference must be applied to produce an electric field that can accelerate an electron to a velocity of 10 raised to 7 meters per second?
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