The idea is to divide force / area. Ask a separate question if you need help to find the area of the circle. And be sure to convert the area of the circle to square meters (1 meter = 1000 mm, therefore, 1 square meter = 1 million square millimeters). Note: Don't get too surprised if the answer is a large number.
F=(MV2)/R Where F is centripetal force, M is the mass of the object, V is the straight-line velocity of the object and R is the radius of the circle it is travelling in.
I assume you mean "uniform circular motion". That means that:* An object moves in a circle, and * The speed, and therefore also the angular speed, is constant. As an example, this occurs in many machines that have rotating parts.
No. There is no outward force exerted in circular motion. Inertia is the reasoning. For example, if your in a car going around a roundabout than you are going one way but the car is going the other hence Inertia is present.
Wind is caused by differences in air pressure from place to place. If you look at a weather forecast map, you should see lines of equal pressure, these are called isobars. If you see a large area of equal pressure, the winds in that area will be light, this is called an anticyclone. If you see an area with the isobars close together there will be strong winds there. In extreme cases usually in tropical areas where there is a high amount of power from the sun, the isobars will form a circle with a very low pressure in the centre, and a hurricane will be formed.
A circle is complete and a cycle repeat
P = ( h ) ( d ) ( g )P = ( 5 m ) ( 1000 kg/m^3 ) ( 9.807 m/s^2 ) = 49035 N/m^2 = 49035 PaP = ( 49035 Pa ) ( 1.01325 bar / 101325 Pa )P = 0.4904 bar
I assume that you are asking about the definition of a circle. A circle is a locus of points in a plane that are at a constant distance from a fixed point.
I would assume that it is going to be round.
id assume there are 6!
I assume you mean a polygon inscribed in a circle. It is regular if all its sides and angles are equal.
Assume the shape is half circle. The area of the circle is: A = πr² where r is the radius Since the semi circle has half the area of the circle, we obtain: A = πr²/2
They must be congruent.
A barometer is an instrument used to measure atmospheric pressure. A circle does not have a barometer!
F=(MV2)/R Where F is centripetal force, M is the mass of the object, V is the straight-line velocity of the object and R is the radius of the circle it is travelling in.
I assume you mean radius of a circle, which is just half the diameter. So you measure the distance across the circle at the widest point, and then divide by two
its a circle with numbers in order to read/measure the atmospheric pressure a circle with numbers to measure the atmospheric pressure
Rewrite the above program so that the program accepts any value for the radius then recalculate the area of the circle.