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What pressure will be exerted by 2.01 mol hydrogen gas in a 6.5 L cylinder at 20 and degC?
Wiki User
∙ 7y ago
PV = nRT
P = nRT/V where P=atm; n=moles; R=gas constant; T=ºK; and V=liters
P =(2.01 mol)(0.0821 Latm/ºKmol)(293ºK)/6.5 L
P = 7.43 atm = 7.4 atm (to 2 significant figures)
Wiki User
∙ 7y ago
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