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Horizontal
the horizontal component remain unchanged because there in no acceleration in horizontal direction
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
A projectile will travel on a straight line unless external forces act upon it. Gravity will pull the projectile downward, i.e. affect its vertical velocity component. This is why the projectile will decelerate upwards, reach a maximum elevation, and accelerate back down to earth. The force vector of air resistance points in the opposite direction of motion, slowing the projectile down. For example, If the projectile is going forward and up, air resistance is pushing it backwards (horizontal component) and down (vertical component). Without air resistance, there is no external force acting upon the horizontal velocity component and the projectiles ground speed will stay constant as it gains altitude and falls back down to earth.
Whether projected horizontally or in an inclined direction ie obliquely the path traversed will be parabolic
Horizontal
the horizontal component remain unchanged because there in no acceleration in horizontal direction
-- In what direction should a projectile be launched in order to achieve the maximum range ? -- Toward 45 degrees above the horizontal.
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
A projectile will travel on a straight line unless external forces act upon it. Gravity will pull the projectile downward, i.e. affect its vertical velocity component. This is why the projectile will decelerate upwards, reach a maximum elevation, and accelerate back down to earth. The force vector of air resistance points in the opposite direction of motion, slowing the projectile down. For example, If the projectile is going forward and up, air resistance is pushing it backwards (horizontal component) and down (vertical component). Without air resistance, there is no external force acting upon the horizontal velocity component and the projectiles ground speed will stay constant as it gains altitude and falls back down to earth.
Whether projected horizontally or in an inclined direction ie obliquely the path traversed will be parabolic
rainbow trajectory
Because there's no horizontal force acting on it that would change its horizontal component of velocity. (In practice, that's not completely true, since the frictional 'force' of air resistance acts in any direction. But outside of air resistance, there's nothing else acting horizontally on the projectile.)
That means the if you change one you do not necessarily change the other. In the case of the projectile the vertical component is dependent on time (if it is a projectile near a large mass like the earth) gravity acts on it accelerating the projectile in a downward direction. The horizontal component remains the same during the entire flight (if we disregard air resistance and such things).
If the non-horizontal projectile is launched abovehorizontal, thenit's the second one to hit the ground, after the horizontal one.If the non-horizontal one is launched below horizontal, then it'sthe first to hit the ground, before the horizontal one.
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.