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A 1kg object is moving at 10 ms to double its kinetic energy its speed should be increased to approximately?
To double its kinetic energy, the object's speed should be increased to approximately 14.1 m/s. This is because kinetic energy is directly proportional to the square of the object's speed (KE = 1/2 * m * v^2). Doubling the speed quadruples the kinetic energy.
What happenes to the temperature as the sun s radiant energy toughes it?
I will assume that by "toughes" you mean "touches". However, you still need to clarify what you mean with "it". In general, if radiant energy falls on an object, the tendency is for the object to heat up. However, objects will also emit radiation, at the same time they receive radiation, and it's entirely possible for an object to lose energy faster than it receives energy from sunlight.
What is a closed experiment?
when energy cannot move through the object(s)
How is potential energy determined?
Potential Energy is calculated by the product of the mass of the object ( not weight! ), the gravitational acceleration ( 9.81 m/s/s ) and the height of the object above a datum. mass x 9.81 x height
If a raised object has potential energy does it have more if you lift it higher?
Yes. The potential energy of an object is E=mgh where m=mass, g=acceleration of gravity (9.8 m/s^2) and h is the height of an object above a reference point. So, if two objects (on the same planet) have the same mass, the one that is higher will have the larger potential energy. Another way to think of this is that in lifting an object higher you do work on that object. That work is converted into it's potential energy. Whenever you do work you change the energy of the object.
1000 kg moving 1 m s or 70 kg at 8 m s?
If the question is analyzed by a non-relastivistic approach of the kinetic energy due to the relatively low velocity of the objects, the equation is: K = 0.5mv² where: K: kinetic energy (Joules) m: mass of the object (kg) v: velocity of the object (m/s) The kinetic energy of object 1 at 1000 kg and 1 m/s is: K1 = 0.5(1000kg)(1m/s)² = 500 kg-m/2 = 500 J The kinetic energy of object 2 at 70 kg and 8 m/s is: K2 = 0.5(70kg)(8m/s)² = 2240 J If higher energy is preferable, than select object 2. If lower energy is preferable, than select object1.
How do you find potential energy of an object?
Potential Energy = mass * 9.80 m/s^2 * height PE = mgh
What influences the kinetic energy of an object?
The mass and velocity of an object determine the kinetic energy of an object. The equation for kinetic energy is KE = 1/2mv2, where m is mass in kg, and v is velocity in m/s.
What is the potential energy of an object that has a mass of 40 kg at a height of 17 meters?
The potential energy of an object can be calculated using the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height. Plugging in the values, we get: PE = 40 kg * 9.81 m/s² * 17 m = 6661.2 Joules.
Calculate the potential energy of a 5.00 kg object sitting on a 3.00 J of energy?
The potential energy of an object is given by the equation PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s^2 on Earth), and h is the height of the object. Since no height is given, it's unclear how to calculate the potential energy in this case.
What is the kinetic energy of an object with a mass of 125 kg, moving at 60 m/s?
225,000 Joules
How is gravitational potential energy determined?
Potential Energy is calculated by the product of the mass of the object ( not weight! ), the gravitational acceleration ( 9.81 m/s/s ) and the height of the object above a datum. mass x 9.81 x height
