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I believe the sample was Curtis Mayfield
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∙ 14y ago
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How do you passivate heat exchanger tubes and it is advisable.?
To passivate an exchanger gently pat the shell while whispering into a bleeder
How do you praise my self?
well, when you complete something that you are proud of, smile at yourself, give yourself a pat on the back, or reward yourself with a treat or a walk or something
What is a catchpot?
A Catchpot (GB Pat No 2302394) was invented by UK inventor Dennis Henson. A Catchpot is a container device used to catch some of the water flowing from float operated water valves. The Catchpot has bleed holes and internal siphon's and is usually attached to the lever arm of the valve. The Catchot's purpose is to create a delay in the opening and closing of the valve and improve the valves flow performance.The word Catchpot is a registered trademark of Henson Delayed Valves Ltd.Read more: What_is_catch_pot
How do you become expert javascript?
Just like learning any other programming language, you must first grasp the concept or the gem of the language. For C++ it was the improvement over C by bringing in the OOP(object oriented programming) functionality. For JavaScript it is, in my opinion, the expandability. You must keep in mind that also the application of these languages are drastically different. JavaScript is a scripting language aimed and applied on the Web, C and other compiled languages are mostly geared at Desktop Applications. Once you grasp the gem, comes the syntax and the pre-built functions. Once you are feeling comfortable with those concept and you grasp the OOP ideal - you can move onto the more Javascript specific realm. Things like prototypes... At that point you can pat yourself on the back and test yourself. If you can program almost anything you need in Javascript good job. A good try would be to write your own Javascript library (like jQuery for example).
What is the difference between base class pointer and derived class pointer in c plus plus?
Your understanding of is a in C++ (polymorphism, in general) is wrong. A is B means A has at least the properties of B, possibly more, by definition. This is compatible with your statements that a Dog has a Pet and that [the attributes of] a Pet is[are] a subset of [attributes] of Dog. It's a matter of definition of polymorphism and inheritance. The diagrams you draw are aligned with the in-memory representation of instances of Pet and Dog, but are misleading in the way you interpret them. Pet* p = new Dog; The pointer p is defined to point to any Pet-compatible object, which in C++, is any subtype of Pet (Note: Pet is a subtype of itself by definition). The runtime is assured that, when the object behind p is accessed, it will contain whatever a Pet is expected to contain, and possibly more. The possibly more pat is what the Dog in your diagram is. The way you draw your diagram lends to a misleading interpretation. Think of the layout of class-specific members in memory: Pet: [pet data] Dog: [pet data][dog data] Cat: [pet data][cat data] Now, whenever Pet *p points to, is required to have the [pet data] part, and optionally, anything else. From the above listing, Pet *p may point to any of the three. As long you use Pet *p to access the objects, you may only access the [pet data], because you don't know what, if anything, is afterwards. It's a contract that says This is at least a Pet, maybe more. Whatever Dog *d points to, must have the [pet data] and [dog data]. So the only object in memory it may point to, above, is the dog. Conversely, through Dog *d, you may access both [pet data] and [dog data]. Similar for the Cat. Let's interpret the declarations you are confused about: Pet* p = new Dog; // [1] - allowed! Dog* d = new Pet; // [2] - not allowed without explicit casting! My understanding is that 1 should not be allowed without warnings because there is no way a pointer should be able to point to an object of its superset's type (Dog object is a superset of Pet) simply because Pet does not know anything about the new members that Dog might have declared (the Dog - Pet subset in the diagram above). The pointer p expects to find [pet data] at the location it points to. Since the right-hand-side is a Dog, and every Dog object has [pet data] in front of its [dog data], pointing to an object of type Dog is perfectly okay. The compiler doesn't know what else is behind the pointer, and this is why you cannot access [dog data] through p. The declaration is allowed because the presence of [pet data] can be guaranteed by the compiler at compile-time. (this statement is obviously simplified from reality, to fit your problem description) 1 is equivalent of an int* trying to point to a double object! There is no such subtype relationship between int and double, as is between Dog and Pet in C++. Try not to mix these into the discussion, because they are different: you cast between values of int and double ((int) double is explicit, (double) int is implicit), you cannot cast between pointers to them. Just forget this comparison. As to [2]: the declaration states "d points to an object that has [pet data] and [dog data], possibly more." But you are allocating only [pet data], so the compiler tells you you cannot do this. In fact, the compiler cannot guarantee whether this is okay and it refuses to compile. There are legitimate situations where the compiler refuses to compile, but you, the programmer, know better. That's what static_cast and dynamic_cast are for. The simplest example in our context is: d = p; // won't compile d = static_cast<Dog *>(p); // [3] d = dynamic_cast<Dog *>(p); // [4] [3] will succeed always and lead to possibly hard-to-track bugs if p is not really a Dog. [4] will will return NULL if p is not really a Dog. I warmly suggest trying these casts out to see what you get. You should get garbage for [dog data] from the static_cast and a NULL pointer for the dynamic_cast, assuming RTTI is enabled.
What is Project Pat's birthday?
Project Pat was born on February 8, 1973.
When was Project Pat born?
Project Pat was born in 1972, in Memphis, Tennessee, USA.
What gang is project pat in?
Project Pat is not in any gang. The previous information was wrong.
What is the birth name of Project Pat?
Project Pat's birth name is Patrick Rasheed Houston.
What movie and television projects has Project Pat been in?
Project Pat has: Played Big Pat in "Three 6 Mafia: Choices - The Movie" in 2001. Played himself in "Jackass Number Two" in 2006. Played himself in "Jackass 2.5" in 2007. Played himself in "Memphis or Die: The Movement - Vol. 1" in 2007. Played himself in "Rhyme and Punishment" in 2011.
How tall is project pat?
6 8
How much does project pat weigh?
Too much.
Which Project Pat song contains whistling?
Cracka Head
What actors and actresses appeared in The Orchestrion Project - 2012?
The cast of The Orchestrion Project - 2012 includes: Pat Metheny as Artist
What are two choices the president has when presented with a bill?
Pay it or don't pat for it just let the light go out.
Who sings song that begins 'red rum red rum'?
Project Pat - Red Rum.
How many children does project pat have?
Yes what i know is that he has one daughter and one son. I know this because i used to live across the street from his ex wife son and daughter that he left.
