A square.
No, only in a square (regular parallelogram).The opposite angles are EQUAL in a parallelogram, and the adjacent angles are SUPPLEMENTARY(they equal 180 degrees).So if any angle in a parallelogram is a right angle, they all are. Otherwise, there are no right angles.The angles of a parallelogram will average 90 degrees, as there are 360 degrees in any quadrilateral, (360/4 - 90) and 180 degrees in two adjacent non-equal angles (180/2 = 90).
Perpendicular lines meet(Intersect) at 90 degrees.
No.
Generally false. In a parallelogram, the opposite angles are equal. They could be complementary in a highly skewed parallelogram in which one angle is 45 degrees.
It is a square, a regular parallelogram with all right angles. The reason is that in a parallelogram, the adjacent angles are supplementary (equal 180 degrees).In any case, the opposite angle would be 90 degrees as well, leaving just 180 degrees for the other two identical opposite angles.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
Only if the parallelogram is in the form of a rhombus will its diagonals bisect each other at right angles
The best classification for a parallelogram that has perpendicular diagonals is a rhombus. A rhombus has four sides that are congruent. The also diagonals bisect the vertex angles of this type of parallelogram.
A rhombus is a type of a parallelogram and its diagonals are perpendicular which means that they intersect each other at right angles.
Not for every parallelogram. Only for a rhombus (diamond) or square will the diagonals bisect the opposite angles they connect, and diagonals are perpendicular. In rectangles, the diagonals do not bisect the angles and are notperpendicular, but they do bisect each other.
Yes the perpendicular diagonals intersect at right angles or 90 degrees
The diagonals of a parallelogram do not intersect each other at right angles and so therefore they aren't perpendicular to each other.
It is true only when the parallelogram is in the form of a rhombus, and thus the two diagonals are perpendicular to each other.
No, the diagonals of a parallelogram do not necessarily bisect the angles. The diagonals of a parallelogram divide it into four congruent triangles, but they do not necessarily bisect the angles of those triangles.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
A rhombus is a parallelogram with all 4 sides congruent. The diagonals bisect(split in have) the interior angles. The diagonals are perpendicular to each other.
yes. They are. because it is both equilateral and equiangular, the diagonals are at the same angles to the sides (45 degrees) and that angle makes them perpendicular.