There are too many variables to consider for your application. You should consult a qualified engineer for this project.
I do believe that it's between 1000 and 1200 feet
you would need 5 pounds for 2000 sqft
Ernie Beam is 6 feet tall. He weighs 185 pounds. He throws right.
A W8x35 steel I-beam, which is 8 inches in depth and weighs 35 pounds per foot, weighs approximately 35 pounds for each foot of length. Therefore, a 22-foot-long W8x35 I-beam would weigh about 770 pounds (35 pounds/foot × 22 feet).
Large males can be over nine feet tall and weigh 1200 pounds and more.The largest Kodiak bear was ten feet long, and weighed 1656 pounds.
To determine how many 2x6's on end are needed to support 1200 pounds over an 8-foot by 8-foot area, you first need to calculate the load per square foot. The area is 64 square feet (8x8), so 1200 pounds divided by 64 square feet equals 18.75 pounds per square foot. A 2x6 on end can typically support around 50-75 pounds per linear foot, depending on the wood type and spacing. Therefore, you would likely need at least 4 to 6 2x6's spaced appropriately to safely distribute the load.
The answer is 100 feet.
1200 yards * 3 feet/yard = 3600 feet
900 * 1200 = 1080000 sq feet
1200 feet = 400 yards.
1200 X 1200 = 1440000 square feet 1440000 / 43560 = 33.057 acres There are 43560 square feet in an acre
Exactly 1200 square feet!