It is not the number of bulbs that you worry about. It is the wire size that is your concern. If the circuit is wired with AWG 12/2 wire then use a 20 amp breaker. If it is wired with a AWG 14/2 wire then use a 15 amp breaker. You are protecting the wiring with the correct size breaker.
A breaker is sized by the wire size. The wire is sized by the amperage. The formula for amperage is I = W/E. Amps = Watts/Volts. As you can see with no voltage stated an answer can not be given.
The breaker protects the wiring not the boiler. 12,000 watts at 240 volts will require 50 amps. So, you will need a 60 amp breaker using AWG# 6 wire on a dedicated circuit.
The question isn't the number of amps total on your branch circuits, but rather, what your MAIN breaker(s) are rated at. This will determine what size of generator you will need. And be certain that the generator is 3-phase. <<>> The formula you are looking for is Amps = kva x 1000/1.73 x voltage.
The use of a breaker in a circuit is to protect the wire size used in the circuit from becoming overloaded. Using the wattage of the load does not help for breaker sizing because the breaker operates on amperage. Amperage can be found from wattage by using the following equation. I = W /E. Amps = Watts / Volts. As you can see the amperage can not be calculated because there is no voltage stated.
3000 / 240 = Amps. You de-rate a breaker by 20 % for continuous load like an oven. You could get by with a 20 Amp breaker and 12 AWG wire. However, I would recommend 30 Amps and 10 AWG for an oven for the long run.
A breaker is sized by the wire size. The wire is sized by the amperage. The formula for amperage is I = W/E. Amps = Watts/Volts. As you can see with no voltage stated an answer can not be given.
If it is a portable generator the breaker should be self contained within the generators panel. If the generator is a stationary standby unit a voltage has to be stated to calculate the conductor size and hence the breaker size to protect the conductor. Amps = Watts/Volts.
15,000 watts at 240 volts will use 62.5 amps. Therefore you will need to use AWG #3 wire on a 100 amp breaker.
The sizing of a breaker is dependant upon the size of the wire it protects. The size of the wire is dependant upon what the load current in amps is. Without the amperage and wattage and the voltage of the appliances an answer can not be given. W = A x V, Amps = Watts/ Volts.
The breaker protects the wiring not the boiler. 12,000 watts at 240 volts will require 50 amps. So, you will need a 60 amp breaker using AWG# 6 wire on a dedicated circuit.
50amp but if considering the breaker cannot withstand starting current you need to size the breaker up.
Yes as long as you use the correct size breaker.
Ovens typically run at 240 volts which will be a two pole breaker in your panel. Watts = volts x amps. 4800 / 240 = 20 amps. If by chance you are using 120 volts then double it to 40 amps. All wiring must conform to size of breaker used.
You need a 60 amp breaker.
Usually 30 Amp 240 volts, but there will be a spec on the well pump.
20 amp In North America code states a two pole 15 amp breaker will do the job.
500 amp breaker with 250 mcm cu conductors, NEC list this motor as drawing 192 amps X 250% = 480amps go to the next standard size of breaker which would be a 500.