Air return duct and filter grille size is dictated by the size of the unit (CFM) not the size of the house.
if the area given is 100 square inches you can use 10" by 10" duct due to a black art known as aerodynamics or compressible fluid flow, you will get the same back pressure in a 10" diameter round duct and a 2" x 50" duct considerably more back pressure a nice manufactured 90 will take as much back pressure as 50' of duct a tight curved 90 will take as much as 100 feet of duct fans have a curve that goes from maximum cfm at no pressure to minimum cfm at max pressure the fan will require the most power when cfm * pressure is highest simple as rocket science i guess
You need 350 to 400 cfm per ton (12,000 btu) of cooling. So, divide your cfm by 400. For example, a 1200 cfm blower on an air handler could handler up to 3 tons. All calculations depend on your duct being the proper size for the equipment.
answer is
Airwatts cannot be compared to miles per hour when considering air flow in vacuum systems. This is because the size of the ducts can vary (though there are some standards). With a given size duct, it is possible to discover the speed of the air flow if all other factors are known. A factor in computing airwatts is flow rate in CFM. Think one thing through: if air is moving at a given speed through a given duct, increasing the duct size (cross section) will cause air speed through the larger duct to go down for the same volume (in CFM) of air flow.
2000 cfm. 400 a ton.
To calculate the formula for duct sizing divide the room load by the whole house load. Next multiply those results by the equipment CFM.
24" round duct or equal. register should be about 2 cfm per sq. inch. or 800 sq. inches for 4 tons
2000 cfm
If you know the FPM and you know the area of your flow say duct work (20"x20")...first convert your area 20*20=400 in2 to Ft220"*20" = 400in2 400in2/144 = 2.7777Ft2Now that you know the area in Ft2 you can use the equation [ FPM*area(ft2) = CFM ]if your FPM is 500 and we use the 20"x20" duct then500fpm * 2.777Ft2 = 1388.5 cfm
It depends. If your bedroom has a supply AND return duct, then no. If there is only a supply duct, and you shut your bedroom door, this pressurizes the bedroom and limits the CFM delivered into the bedroom. A room to room vent or duct would equalize this pressure and allow maximum CFM to be delivered from the central air/heat system.
5000mmx1000mm..