Looks like You need to run #10 to get 10 amps at 600 feet. You will have a voltage drop. You might only have aprox. 107.676 volts at the end of the run. You will do a little better if you use strand wire. Good luck.
A 300 MCM copper conductor, with a voltage drop of 3%, is needed when supplying 50 amps for 600 feet on a 120 volt system.
You would need a #10 copper wire over the length of 100 feet to give you a working load of 10 amps at 120 volts. That will hold to voltage drop to 3% of the supply voltage.
This is a voltage drop question and the circuit's voltage must be stated.
I would recommend AWG # 10.
12
18 amps.
A mile is 5280 feet, which is 1760 yards. So, 1000 yards is 1000/1760 = 0.568 miles.
50 x 20 = 1000 So the yard is 1000 square feet
This is a voltage drop question. A voltage at 30 amps needs to be stated to answer the question.
1000 feet
12
It depends on the definition of a room. What would the minimum width or length measurement be in a space, and still have it considered a room? With a minimum dimension to go off of, must the product of the width and length be exactly 1000 square feet? Must the width and length be in whole numbers?
Just under 32 revolutions
1000 feet remains 1000 feet if the distance is measured in feet.
1000 feet
if u can still c the air craft it is about 1000 feet of altitude
no
150 amps
Multiply width by length to get the area. The answer would be 1000 square feet.
There are 3 feet in one yard. Therefore, 1000 feet is equal to 1000/3 = 333.3 recurring (that is, 333.3333...) feet.
18 amps.