Iron(II) carbonate [green] to Iron(II) oxide.
The anhydrous molecule or species. e.g. CuSO4.5H2O (hydrate) + heat ----> CuSO4 (anhydrous) + water vapor
I would assume that the water evaporates.
Iodine is a purple-black non metal that changes to a deep purple gas when heated.
The residue obtained from heating crystals of FeSO4 (iron(II) sulfate) is Fe2O3 (iron(III) oxide) and SO2 (sulfur dioxide) gases. This is because the heating process causes the iron(II) sulfate to decompose, releasing water vapor, sulfur dioxide gas, and leaving iron(III) oxide as a solid residue.
crystalline gets hotter then amorphous
Carbon residue is deposits of solid black residue from burnt carbon.
A solid insoluble residue remain after the evaporation of water.
The gas and the solid are two different compounds, they won't be the same therefore they'd be a mixture.
Solid residue is what remains after a liquid evaporates.
What is left after heating sucrose is charcoal or solid carbon (C2). Heating causes sucrose to decompose as referred to this chemical reaction: C12H22O11 + O2 (the air is filled with it) - Heated --> CO2 + H2O + C2
Either sodium carbonate or copper carbonate
The anhydrous molecule or species. e.g. CuSO4.5H2O (hydrate) + heat ----> CuSO4 (anhydrous) + water vapor
After the total evaporation of water a small solid residue can remain in the beaker.
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carbon
I would assume that the water evaporates.
The green powder is copper (2) carbonate. When heated it decomposes to give copper (2) oxide (which is black) and carbon dioxide . It is a compound.