The power in the wave is [ 30 dB = 1,000 times ] greater.
Given: Sound intensity level LI1 = 40 dB and sound intensity level LI2 = 20 dB. Reference sound intensity Io = 10^−12 W/m² (Threshold of hearing) Reference sound intensity level LIo = 0 dB-SIL (Threshold of hearing level) Get sound intensity I1 when entering sound intensity level LI1 = 40 dB: Sound intensity I1 = Io×10^(LI/10) W/m² = 10^−12×10^(40/10) = 0.00000001 W/m² = 10^−8 W/m². Get sound intensity I2 when entering sound intensity level LI2 = 20 dB: Sound intensity I2 = Io×10^(LI/10) W/m² = 10^−12×10^(20/10) = 0.0000000001 W/m² = 10^−10 W/m². The sound intensity I1 = 10^−8 W/m² is 100 times more than the sound intensity I2 = 10^−10 W/m². The sound intensity level LI1 = 40 dB is 20 dB more than the sound intensity level LI2 = 20 dB.
10 times.
(90 dB - 70 dB) = 20 dB = 100 times as much sound power.(100 times 'as much' = 99 times 'more')
Better think of the sound pressure, when you are listening. Sound pressure moves your ears and the diaphragm of the microphones. The sound intensity is very small. The level of 50 dB is equal to 0.0000001 W/m2 acoustic intensity. Scroll down to related links and look at "Conversion of sound units (levels)".
The power in the wave is [ 30 dB = 1,000 times ] greater.
Reference sound intensity Io = 10^−12 W/m² (Threshold of human hearing). Reference sound intensity level LIo = 0 dB-SIL (Threshold of human hearing intensity level). The sound intensity I is measured in watts per meter squared. The sound intensity LI level is measured in decibels (dB).
Given: Sound intensity level LI1 = 40 dB and sound intensity level LI2 = 20 dB. Reference sound intensity Io = 10^−12 W/m² (Threshold of hearing) Reference sound intensity level LIo = 0 dB-SIL (Threshold of hearing level) Get sound intensity I1 when entering sound intensity level LI1 = 40 dB: Sound intensity I1 = Io×10^(LI/10) W/m² = 10^−12×10^(40/10) = 0.00000001 W/m² = 10^−8 W/m². Get sound intensity I2 when entering sound intensity level LI2 = 20 dB: Sound intensity I2 = Io×10^(LI/10) W/m² = 10^−12×10^(20/10) = 0.0000000001 W/m² = 10^−10 W/m². The sound intensity I1 = 10^−8 W/m² is 100 times more than the sound intensity I2 = 10^−10 W/m². The sound intensity level LI1 = 40 dB is 20 dB more than the sound intensity level LI2 = 20 dB.
The 40dB sound is (40 - 20) = 20 dB louder than the 20 dB sound.20 dB louder = 10(20/10) = 102 = 100 times louder
10 times.
(90 dB - 70 dB) = 20 dB = 100 times as much sound power.(100 times 'as much' = 99 times 'more')
Better think of the sound pressure, when you are listening. Sound pressure moves your ears and the diaphragm of the microphones. The sound intensity is very small. The level of 50 dB is equal to 0.0000001 W/m2 acoustic intensity. Scroll down to related links and look at "Conversion of sound units (levels)".
If you think the threshold of pain is the sound intensity level of LI = 120 dB than you can convert that value to sound intensity I. Reference sound intensity Io = 10^−12 W/m² (Threshold of hearing). Reference sound intensity level LIo = 0 dB-SIL (Threshold of hearing level). Get sound intensity I when entering sound intensity level LI = 120 dB. Sound intensity I = Io×10^(LI/10) W/m² = 10^−12×10^(120/10) W/m² = 1 W/m².
No, 10 dB is perceived to be twice as loud, and requires 10 times the power.Doubling of the volume (loudness) should be perceived by a level difference of 10 dB − psychoacousticians say.Doubling the sound pressure (voltage) level corresponds to a measured level change of 6 dB.Doubling of acoustic power (sound intensity) level corresponds to a calculated level change of 3 dB.Scroll down to related links and look at "How many decibels (dB) is twice (double, half) or three times as loud?"
dB stands for decibel and is used to measure sound intensity in acoustics
When doubling the field quantity factor by 2 the level increases by 6 dB. When doubling the energy quantity factor by 2 the level increases by 3 dB. When doubling the sound pressure value by 2 the level increases by 6 dB. When doubling the sound intensity value by 2 the level increases by 3 dB. The decibel (dB) is a logarithmic unit that indicates the ratio of a physical quantity relative to a specified or implied reference level. You usually don't double decibels - you double the factor (ratio). Look at the link "Subjectively perceived loudness (volume), objectively measured sound pressure (voltage), and theoretically calculated sound intensity (acoustic power)".
Sound intensity is inversely proportional to the square of the distancefrom the source.-- Increase the distance from the source by 10 times.-- Sound intensity decreases to 1/102 = 1/100 .-- 10 log ( 1/100 ) = -20 dB-- 100 dB - 20 dB = 80 dB