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The mass, 5.00 g, must be converted to moles. The molar mass of Cl2 is 71 g/mole. Also convert 750 ml to 0.75 L

5.00 g x (1mole / 71 g) = 0.0704 mol

(PV / nT)a = (PV / nT)b ; where a and b represent different conditions

(120 kpa)(0.75 L) / [(0.0704 mole)(T)] = (101.325 kpa)(22.4 L) / [(1 mole)(273 K)]

Solve for T, the unknown temperature.

T = (1 mole)(273 K) / [(101.325 kpa)(22.4 L)] x [(120 kpa)(0.75 L)] / (0.0704 mol)

T = 153.7 K round to 154 K

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Q: What temperature will 5.00g of cl2 exert a pressure of 120kpa at a volume of 750ml?
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