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9.28 g
To find out how many grams of N2 are needed to produce 1.7 grams of NH3, you need to look at the balanced chemical equation for the reaction. For the reaction N2 + 3H2 -> 2NH3, the molar ratio of N2 to NH3 is 1:2. So you would need half the number of grams of N2 as NH3, which is 0.85 grams of N2.
Gas has no shape; therefore, nitrogen gas can have no definite shape.
To determine the mass of ammonia (NH3) that can be produced from 35.0 grams of nitrogen gas (N2), we first need to use the balanced chemical equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. The molar mass of N2 is approximately 28.02 g/mol, allowing us to calculate the number of moles of N2 in 35.0 grams as about 1.25 moles. Since 1 mole of N2 produces 2 moles of NH3, 1.25 moles of N2 will yield 2.5 moles of NH3. The molar mass of NH3 is about 17.03 g/mol, so 2.5 moles of NH3 corresponds to approximately 42.58 grams.
-3 because it is located in the 5th group of the periodic table.
10 grams of N2 would have a greater number of molecules than 10 grams of O2 because nitrogen (N2) has a smaller molar mass compared to oxygen (O2), so there would be more nitrogen molecules in 10 grams.
Use equation n=PV/RT where n is number of moles and R is gas constant. Use R= .8314 L-Atm/mol-K. convert 3 ml to liters(3/1000) and 100C to Kelvin (100+273) and solve for moles. Convert moles to grams. 1 mol of N2 equals 28 grams
394.794 grams
16,45 g nitrogen are needed.
I believe it is N2 which is a gas at room temperature.
To find the mass of N2, first calculate the moles of N2 using the ideal gas law: PV = nRT. Then use the molar mass of N2 to convert moles to grams. Given that the volume is 3.0 L, the temperature is 100°C (373 K), and the pressure is 700 mmHg (93.3 kPa), you can substitute these values into the ideal gas law to find the moles of N2.
Nitrogen gas is diatomic, meaning it consists of two nitrogen atoms bonded together (N2).