There is no integral solution, because none of the factor pairs of 16 add to 6.
x +y = -16
x * y = 6
x (-16 - x) = 6
- x2 - 16 x - 6 = 0
x2 + 16 x + 6 = 0
Quadratically, x and y are the two roots: (-8) + (sq rt 58) and (-8) - (sq rt 58)
Check: (-8 +sq rt 58)*(-8 -sq rt 58) = 6 and (-8 +sq rt 58)+(-8 -sq rt 58) = -16
They are about: 0.53112887 and -7.53112887
5 and 12
13
unfactorble i think
80
-78
141
962
28
21
The numbers are: -4 +square root of 12 and -4 -square root of 12
There are no two real numbers that do, but the complex numbers (2 + i) and (2 - i) will.If you want two numbers that multiply to negative 5 and add to positive 4 then: -1 and 5If you want two numbers that multiply to negative 5 and add to negative 4 then: 1 and -5