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The ionic compound BaSe is called barium selenide.
Barium and tin can form an ionic bond where barium, a metal, transfers electrons to tin, a metalloid. This creates a bond where barium becomes positively charged as it loses electrons and tin becomes negatively charged as it gains electrons.
BaF2 is an ionic bond. Barium (Ba) is a metal, while fluorine (F) is a nonmetal. When they combine, barium loses electrons to fluorine, resulting in the formation of positively charged barium ions and negatively charged fluoride ions that are held together by electrostatic forces.
BaCl2 forms an ionic bond. In this bond, the barium atom, which is a metal, donates electrons to the chlorine atoms, which are nonmetals, resulting in the formation of positively charged barium ions and negatively charged chloride ions that are held together by electrostatic interactions.
The ionic compound of BaSe is barium selenide. Barium (Ba) is a metal with a 2+ charge, and selenium (Se) is a nonmetal with a 2- charge. When they combine in a 1:1 ratio, they form an ionic compound with the formula BaSe.
The ionic compound BaSe is called barium selenide.
Barium selenide is BaSe.
Barium Selenide ---> Ba2+Se2- ---> BaSe
Barium Selenide
Barium selenide is not soluble in water as it is an insoluble compound. When placed in water, it will not dissolve and instead form a suspension or precipitate.
Barium Selenide
Ionic
An ionic bond forms between barium and oxygen.
An ionic compound, Barium selenide or BaSe is formed, with the ions Ba2+ and Se2-.
The chemical equation for the reaction between barium and selenium is: Ba + Se → BaSe. This reaction forms barium selenide.
Barium and tin can form an ionic bond where barium, a metal, transfers electrons to tin, a metalloid. This creates a bond where barium becomes positively charged as it loses electrons and tin becomes negatively charged as it gains electrons.
Barium sulfide contains an ionic bond, with barium (Ba) donating electrons to sulfur (S) to form a stable crystal lattice structure.