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A noble gas electronic configuration has an outer shell of ns2, np6. Examles of ions with this configuration are O2- [He], 2s2 2p6 (the neon configuartion) Cl- [Ne] 3s2 3p6 (the argon configuration)
Noble gases have completely filled orbitals / energy levels. They generally have 8 valence electrons (helium has only 2) and have stable electronic configuration.
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The symbiol depends on the type of noble gas. So its not constant. It may be positive or even negative.
Uranium has 7 electron shells.The electron configuration is [Rn]5f36d17s2.
A noble gas electronic configuration has an outer shell of ns2, np6. Examles of ions with this configuration are O2- [He], 2s2 2p6 (the neon configuartion) Cl- [Ne] 3s2 3p6 (the argon configuration)
Noble gases have completely filled orbitals / energy levels. They generally have 8 valence electrons (helium has only 2) and have stable electronic configuration.
Type your answer here... nElectron Configuration: [ Ne]3s2 3p1
A non-metal atom will form negative ions. The reason for this is because chemical bonding is based on atoms' desire to attain or emulate the electron configuration of inert or noble gases.
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The symbiol depends on the type of noble gas. So its not constant. It may be positive or even negative.
Potassium (K) has an atomic number of 19. The noble gas electron configuration is [Ar]4s^1
Uranium has 7 electron shells.The electron configuration is [Rn]5f36d17s2.
describe the type of electron configuration that makes a atom stable and not likely to react
Assuming you didn't type the incorrect number of electrons for this noble gas, it can be expressed in a couple ways. One is simply by implying its charge, or shown as Kr1-. Another way is to use an electron configuration. You can express Krypton with an extra electron as electrons filling orbitals, shown like this: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 or [Kr] 5s1 (Noble gas notation shortcut)
A condensed (or abbreviated) electron configuration is a way to draw an orbital diagram for a late electron. For this type of diagram the core electrons are replaced with the symbol for the noble gas nearest to the element you are describing. Brackets are put around this symbol and then the outer, valence electrons are described as usual.
A potassium atom "always" loses exactly one valence electron when it reacts with another element, because one valence electron in a potassium atom has a much lower ionization energy requirement than any other electron in the same atom. (This property is generally ascribed to the fact that when a potassium loses exactly one electron, it acquires the very stable electron configuration of the noble gas argon.) A chlorine atom has a very strong attraction (its electronegativity) for exactly one electron, which gives the charged atom the electron configuration of an argon atom. Therefore, when a potassium atom is close enough to a chlorine atom, one electron is transferred between to form an ionic bond and a formula unit of the compound potassium chloride.