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The reaction Zn + CuCl2 --> Cu + ZnCl2 is a single-replacement reaction.
Zn + 2HCl --> ZnCl2 + H2
Double Replacement
When zinc chromate and silver nitrate react, they undergo a double displacement reaction. The products are then silver chromate and zinc nitrate. The complete equation is ZnCrO4 + 2 AgNO3 = Ag2CrO4 + Zn(NO3)2
Zn + 2AgNO3 --> Zn(NO3)2 + 2Ag Keq = [Zn(NO3)2][Ag]^2/[Zn][AgNO3]^2 You need concentrations to calculate the Keq Answer from: http://answers.yahoo.com/question/index?qid=20090210150755AAmWI7s
The reaction Zn + CuCl2 --> Cu + ZnCl2 is a single-replacement reaction.
Zn + 2HCl --> ZnCl2 + H2
Double Replacement
When zinc chromate and silver nitrate react, they undergo a double displacement reaction. The products are then silver chromate and zinc nitrate. The complete equation is ZnCrO4 + 2 AgNO3 = Ag2CrO4 + Zn(NO3)2
Zn + 2AgNO3 --> Zn(NO3)2 + 2Ag Keq = [Zn(NO3)2][Ag]^2/[Zn][AgNO3]^2 You need concentrations to calculate the Keq Answer from: http://answers.yahoo.com/question/index?qid=20090210150755AAmWI7s
They will form NaNO3 in aqueous solution, and AgOH would precipitate out of solution. AgNO3(aq) + NaOH(aq) --> AgOH(s) + NaNO3(aq) This is an example of a double displacement/replacement reaction.
single-displacement reaction
The type of reaction represented by Zn plus 2NaCl yields 2Na plus ZnCl2 is an impossible one. It would be the other way around. 2Na + ZnCl2 --------> 2NaCl + Zn
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl Silver chloride is a white precipitate.
The reaction is: Zn + 2HCl = ZnCl2 + H2
Just write it out: All the coefficients in the equation are 1, as this choice gives the same numbers of each of the same kinds of atoms on the right and left sides of the equation, if the formulas given are correct. However, most if not all zinc nitrate has the formula Zn(NO3)2 rather than the one given in the question. that reaction balances as follows:Zn + 2 AgNO3 = Zn(NO3)2 + 2 Ag.
AgNO3