The reduction half-reaction for this reaction is: Zn^2+ + 2e- -> Zn(s).
NO3-
The ionic compound ZnS is zinc sulfide.
Zinc sulfide
Um, I don't know about the other compounds, but ZnS is insoluble.
The half-reaction for this redox reaction could be written as: Zn(s) -> Zn2+(aq) + 2e-. This indicates the oxidation of solid zinc (Zn) to zinc ions (Zn2+) and the release of 2 electrons.
Zn^2+ + 2e- ––> Zn(s)
It is the zinc that gets reduced, and the magnesium that gets oxidised. This is because zinc has the higher reduction potential of -0,76 V, compared to magnesiums -2,37 V. The oxidation half cell therefore becomes Mg (s) --> Mg2++ 2e-
NO3-
ZNS-TV was created in 1977.
ZNS - performer - was born on 1989-08-04.
The ionic compound ZnS is zinc sulfide.
Zinc sulfide
Assuming you mean ZnS, it's a compound - Zinc sulfide.
Bulk ZnS morphology studies focus on larger scale structures of the material, such as crystal size and shape, while nano ZnS morphology studies focus on the nanoscale features, including size distribution, surface area, and the presence of defects and dislocations. Nano ZnS may exhibit different properties due to its smaller size and higher surface area compared to bulk ZnS.
Um, I don't know about the other compounds, but ZnS is insoluble.
The half-reaction for this redox reaction could be written as: Zn(s) -> Zn2+(aq) + 2e-. This indicates the oxidation of solid zinc (Zn) to zinc ions (Zn2+) and the release of 2 electrons.
To determine the grams of ZnS required to react with oxygen gas, we need to write a balanced chemical equation of the reaction. Then we can use stoichiometry to calculate the amount of ZnS needed. Given that the reaction involves ZnS and oxygen gas at STP (Standard Temperature and Pressure), we can use the ideal gas law to find the number of moles of oxygen, which will help us determine the amount of ZnS needed.