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momentum=mass*velocity 1*10=10Ns
After 20 m all kinetic energy have been transformed to potential energy.Epot=m*g*h=0.15*9.81*20=29.4 Joule
if the body of mass of 1kg is thrown at velocity of 9.8m/s?
KE=1/2MV^2 Or in other words, Kinetic Energy = 0.5 x Mass (1000g) x Velocity (measured in metres per second) Squared (make sure you only square the Velocity) For example if your 1kg ball was going at 2 metres per second, then the equation would look like this: KE = 0.5 x 1000 x 4 = 2000 Joules
a lamp or 1 bag of onions
momentum=mass*velocity 1*10=10Ns
Potential Energy = mgh=1kg x 10m/s2 x 34.5m=345kg.m2/s2
After 20 m all kinetic energy have been transformed to potential energy.Epot=m*g*h=0.15*9.81*20=29.4 Joule
if the body of mass of 1kg is thrown at velocity of 9.8m/s?
KE=1/2MV^2 Or in other words, Kinetic Energy = 0.5 x Mass (1000g) x Velocity (measured in metres per second) Squared (make sure you only square the Velocity) For example if your 1kg ball was going at 2 metres per second, then the equation would look like this: KE = 0.5 x 1000 x 4 = 2000 Joules
It should be increased to approximately 14 m/s.
45p
please quickly
0.166 kg
a lamp or 1 bag of onions
1 J= MgZ where Z is the elevation of the object; M=1Kg and g=9.8N/Kg --> 1=(1)(9.8)Z --> Z=0.1 m
You would need to know the specific heat capacity of the object, but presuming we're talking about water and perfect efficiency, you'd need exactly 1 joule.