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What volume of 0.233M H2SO4 is needed to react with 56.6mL of 0.114M NaOH?
Updated: 10/19/2022
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9y ago
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Va * Ma * Ta = Vb * Mb * Tb
in which (subscripts: a=acid, b=base)
V = volume (mL)
M = molarity (mol/L)
T = titre, number of H+ involved per mol acid (H
2
SO4) or base (OH-) respectively)
Va * (0.233*2) = 56.6(mL) * (0.144*1)
Va = 17.5 mL
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Q: What volume of 0.233M H2SO4 is needed to react with 56.6mL of 0.114M NaOH?
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What volume of 0.233M H2SO4 is needed to react with 56.6mL of 0.114M NaOH?