0
What volume of air contains g of oxygen gas at 273 K and 1.00 ATM?
Wiki User
∙ 9y ago
Use temperature and pressure to define the density, air density is 1.293 kg/m3 at 273 K and 1 ATM. You know the mass of air is 14.3 g, convert that to kg first.
Density = mass/volume, just solve volume from known density and mass.
Wiki User
∙ 13y ago
Wiki User
∙ 11y agoAir is approximately 20 % oxygen, so the partial pressure of the oxygen is 0.2 atm.
There are several ways to proceed from here. ... I'll pick one.
13.2 g oxygen / 32 g = 0.4125 mol of oxygen
At STP 1 mole occupies 22.4 L. We have a pressure of 0.2 atm. (temp is std)
PV / nT = PV / nT (temp cancels because it is std on both sides)
(0.2 atm)(V) / (0.4125 mol) = (1 atm)(22.4 L)/(1 mole)
solve for V .... V = (22.4L)(0.4125)/(0.2)
V = 46.2 Liters
Wiki User
∙ 8y agoAssuming you mean 10.7 moles, 273 kelvins and 1.00 atmospheres, plug those values into the Ideal Gas Law equation: PV=nRT (1)(V) = 10.7(0.082)(273), V = 240 liters. You can also get it by simply multiplying moles by 22.4 liters/mole, which is an accepted value of the volume of any gas per mole at STP, which is standard temperature and pressure, since you're at 273K and 1atm.
Wiki User
∙ 11y ago50L
Add your answer:
Earn +20 pts
What is the volume of the gas at 200 degrees c if it is 25 L at 0 degrees c?
Use Charles's Law: V1 / T1 = V2 / T2 Constant pressure must be kept. Absolute temp. must be used. T1 = 0 + 273 = 273 degr.K T2 = 200 + 273 = 473 degr.K 25 L / 273 K = V2 / 473 K V2 = 25 x 473 / 273 = 43.315 L (final volume).
How is absolute zero originally determined?
The volume of gases decreases with temperature; extrapolating the volume/temperature relationship, it looked as if all gases would reach a volume of zero at approximately the same temperature, about minus 273 degrees centigrade.
What would be the volume at STP of 255 ml of CO2 measured at 30C and 85.0 kPa?
turn 0 C to 273 K , 30 C to 303K then 255*85/303=101.3*V/273 V=193mL
What is the volume of a gas that contains 0.425 mol at 57.0 degrees celsius and has a pressure of 3.00 ATM (recall that r 0.0821 L ATM mol k)?
Apply the ideal gas law: PV=nRT: (3.00atm)V=0.425mol(0.0821)(273+57). Solve for V to get 3.8L.
How does the volume of a gas vary?
Pressure and temperature. As pressure increases, volume decreases; as temperature increases, volume increases with it. At standard temperature and pressure (1 atm, 273 degrees Kelvin), one mole of a gas (6.022 x 1023 particles) has the volume of 22.4 liters.
What is 273 as a fraction?
It is 273/1It is 273/1It is 273/1It is 273/1
What is percentage of 2.73?
2.73 as a percentage = 273% 2.73 * 100% = 273%
What is the percentage for 273 out of 300?
It is: 273/300 times 100 = 91%
What is the percent of 273 divided by 2000?
0.1365
What is 273 meters in centimeters?
100cm in 1mTherefore 273 x 100 = 27300cm
What is 100 minus 273?
-173
Abslute Zero is defined as 0 k or -273 C What is the temperature in degrees K of -100 C?
Add 273 to go from temperatures in degrees Celsius to Kelvin. Thus, -100 degrees Celsius is (-100+273=) 173 K.
What is 2.73 in fraction form?
2 and 73/100 (73 over 100), in its simplest form. Alternatively, you could also use 273/100 (273 over 100) if you can't have any whole numbers.
How do you do 2.73 as a percent?
Multiply the decimal by 100: 2.73 x 100 = 273%
How do you write 273 in expanded form?
Expanded Notation of 273 = (2 x 102) + (7 x 101) + (3 x 100) OR (2 x 100) + (7 x 10) + (3 x 1).
What number is 70 percent of 390?
70% of 390 = 273 = 70% * 390 = 70%/100% * 390 = 273
What is 100 C in Kevin scale?
To convert Celsius to Kelvins, add 273 to the temperature in Celsius. Therefore, 100 degrees Celsius plus 273 = 373 K
