What volume will 100 grams of oxygen gas occupy?

Answer 1

100g O2 = 3.125 mol O2 (since 1 mol O2 = 32 g) 25 degrees C = 298 K 1.50 atm remains 1.50 atm Gas constant when dealing with pressure in atm is 0.082 Plug these values into the equation: PV=nRT 1.50 atm x V = 3.125 mol x 0.082 x 298 K V = 50.9 FINAL ANSWER: 50.9 L

Answer 2

Use the general 'Ideal Gas' law:

p.V = n.R.T

or

V = n.R.T/p

p=pressure in atm (atmosphere)

V=volume in Litres

n= number of moles

T=absolute temperature in K (= oC + 273)

and R is the general 'gas constant' = 8.02*10-2 L.atm.K-1.mol-1

Or in Standard international units (SI-units):

p=pressure in Pa (pascal)

V=volume in m3

n= number of moles

T=absolute temperature in K (= oC + 273)

and R is the general 'gas constant' = 8.31 J.K-1.mol-1

This is valid for ANY kind of (ideal) gas (at about normal or low temperature, normal or lower pressure; all of the given values are OK)

Answer 3

Use the ideal gas law:

PV=nRT

Pressure(volume) = moles(gas constant)Temperature

When using the ideal gas equation, n=moles. Therefore, the mass needs to be converted to moles to fit the equation:

Grams ÷ molecular mass = Moles

143.6 grams O2 ÷ 32.0 grams = 4.49 moles O2

.450(v) = 4.49(.0821)356

v = 292 L O2

The gas constant is given and remember that temperatures need to be in Kelvin (oC + 273).

Answer 4

Assuming ideal gas behavior, 100 grams of oxygen gas at standard temperature and pressure (STP) will occupy a volume of approximately 22.4 liters. This value is based on the molar volume of a gas at STP, which is 22.4 liters/mol.

Answer 5

uselah the formula from the book . dont be lazy lah .you have much more time

Answer 6

Any volume you like - it depends on the quantity of O2 you have!

Answer 7

The volume is 70 L.

Answer 8

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