100g O2 = 3.125 mol O2 (since 1 mol O2 = 32 g) 25 degrees C = 298 K 1.50 atm remains 1.50 atm Gas constant when dealing with pressure in atm is 0.082 Plug these values into the equation: PV=nRT 1.50 atm x V = 3.125 mol x 0.082 x 298 K V = 50.9 FINAL ANSWER: 50.9 L
Wiki User
∙ 11y agoAssuming ideal gas behavior, 100 grams of oxygen gas at standard temperature and pressure (STP) will occupy a volume of approximately 22.4 liters. This value is based on the molar volume of a gas at STP, which is 22.4 liters/mol.
Wiki User
∙ 12y agoUse the general 'Ideal Gas' law:
p.V = n.R.Tor
V = n.R.T/pp=pressure in atm (atmosphere)
V=volume in Litres
n= number of moles
T=absolute temperature in K (= oC + 273)
and R is the general 'gas constant' = 8.02*10-2 L.atm.K-1.mol-1
Or in Standard international units (SI-units):
p=pressure in Pa (pascal)
V=volume in m3
n= number of moles
T=absolute temperature in K (= oC + 273)
and R is the general 'gas constant' = 8.31 J.K-1.mol-1
This is valid for ANY kind of (ideal) gas (at about normal or low temperature, normal or lower pressure; all of the given values are OK)
Wiki User
∙ 15y agoUse the ideal gas law:
PV=nRT
Pressure(volume) = moles(gas constant)Temperature
When using the ideal gas equation, n=moles. Therefore, the mass needs to be converted to moles to fit the equation:
Grams ÷ molecular mass = Moles
143.6 grams O2 ÷ 32.0 grams = 4.49 moles O2
.450(v) = 4.49(.0821)356
v = 292 L O2
The gas constant is given and remember that temperatures need to be in Kelvin (oC + 273).
Wiki User
∙ 15y agouselah the formula from the book . dont be lazy lah .you have much more time
Wiki User
∙ 12y agoAny volume you like - it depends on the quantity of O2 you have!
Wiki User
∙ 6y agoThe volume is 70 L.
Madeline Lamy
Hailffb
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
The amount of liquid in 100 grams will vary depending on the density of the liquid. The volume of the liquid can be calculated by dividing the mass (100 grams) by the density of the liquid.
No, 100 milliliters and 100 grams are not the same. Milliliters measure volume, while grams measure mass. The relationship between milliliters and grams depends on the density of the substance being measured.
100g of lead would occupy a larger volume compared to 100g of water because lead has a higher density of 11.34 g/ml, whereas water has a density of 0.995 g/ml. The higher the density of a substance, the more mass it can hold in a smaller volume.
The weight of 100 mL of a substance can vary depending on its density. For water, 100 mL is equal to 100 grams. However, for other substances, you would need to know the density to convert volume to weight.
The density of a material does not change with mass. 100 grams of a material will occupy 10 times the volume of 10 grams of the same material.
The volume depends on the temperature and pressure - neither of which are given.
Ice has a lower density than water, so the same mass of ice will occupy more space compared to water. This is because the molecular arrangement in ice forms a lattice structure that makes it less compact, resulting in a greater volume for the same mass.
When the water froze into ice it was expanding (thermal expanision) causing the 100 grams of ice to have a greater volume than 100 grams of water!
grams are mass, ml's are volume apples and oranges.... however at sea level, standard temp (4 deg C) and pressure 100 ml of water has a mass of 100 g. So in that special condition 100 grams would occupy 100 ml and your answer would be no.
At 4 deg C and at a pressure of 760 mm of mercury, when water is at its highest density, 1000 grams of water will occupy 1000.028 mL. At all other temperatures (pressure = one atmosphere), it will occupy a greater volume. At 100 deg C it will occupy 1043 mL. However, most people will say 1000 grams of water equals 1000 mL.
For every 1 mole of propane burned, 5 moles of oxygen are required. This means that 44 grams of propane requires 160 grams of oxygen to burn completely. Therefore, 100 grams of propane would require (100 grams propane * 160 grams oxygen / 44 grams propane) = 363.64 grams of oxygen to burn completely.
100 grams of water at standard temperature and pressure has a volume of 100 cubic centimeters or 100 millilitres. The volume of 100 grams of any other substance will depend on its specific gravity or density: if less than that of water, it will have a greater volume; if greater than that of water, it will have a smaller volume.
100 cm is a length, not a volume. However, if the volume were 100 cubic cm, the density would be 0.196/100 = 0.00196 grams per cc.
Density is calculated by dividing the mass of an object by its volume. In this case, the density would be 100 grams / 5 grams = 20 grams per cubic gram.
The density is (the mass, in grams)/100 grams per cm3 .
100 lbs of steam. The volume that the steam will occupy will depend on the pressure.