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the gas occupies a volume of37.7 ml as stated in the question either your question is wrong or incomplete.
1075 torr - 720 torr = 355 torr
P1V1 = P2V2 (740 torr)(500 ml) = (780 torr)V2 V2 = (740 torr)(500 ml) / (780 torr) V2 ~ 474 ml
500 mmHg or 500 torr is a gas pressure approximately 66% of the standard sea level air pressure of 760 torr ... it is the air pressure one would find at an altitude of approximately 3km or 10000 feet ... at sea level, 500 torr would be considered a partial vacuum of 0.66 atm.
630 torr
the gas occupies a volume of37.7 ml as stated in the question either your question is wrong or incomplete.
1300<--- torr
The pressure is 39,8 torr.
1100
1100
Boyle's law states that pressure is indirectly proportional to the volume. There fore as the pressure of a gas at 760 torr is changed to 380 torr, the volume will increase. Boyle's Law: P1 x V1 = P2 x V2 Rearranging leads to: P1 / P2 = V2 / V1 Substituting our values: 760 / 380 = V2 / V1 Thus the final volume will be twice the initial volume.
1075 torr - 720 torr = 355 torr
P1V1 = P2V2 (740 torr)(500 ml) = (780 torr)V2 V2 = (740 torr)(500 ml) / (780 torr) V2 ~ 474 ml
I got 321.6mL. You use PV=nRT to find n, and plug that into PV=nRT with the new conditions to find the new volume.
500 mmHg or 500 torr is a gas pressure approximately 66% of the standard sea level air pressure of 760 torr ... it is the air pressure one would find at an altitude of approximately 3km or 10000 feet ... at sea level, 500 torr would be considered a partial vacuum of 0.66 atm.
630 torr
630 torr