.45 LC
No. the AK-47 assault rifle is chambered for the 7.62x39mm round, which is equal to the .30 caliber. The .45 caliber is simply too large for the AK-47's bore, not to mention it is a pistol cartridge, which has a completely different design than a rifle cartridge.
Depends on which cartridge, and there are dozens of different cartridges. A .22 rimfire is about 4 cents per round. Some exotic large caliber ammo is about $3 per round. Tell us which cartridge, and we can get you a better answer.
This might get a little confusing. A TRUE .38 caliber cartridge will be 38/100ths of an inch in diameter. HOWEVER, the cartridge CALLED the .38 Special is not quite that large- it is .357 inches in diameter, or 357/100ths of an inch- just over a third of an inch, or a little more than 9 millimeters.
Caliber is the term used for the diameter of the inside of the barrel (in shotguns, it is called gauge instead). The larger the opening of the barrel (known as the bore) the higher the caliber- but not necessarily the energy of the cartridge. The .600 Nitro Express was a VERY large cartridge used for VERY big game hunting- elephants. But it is an older, straight sided cartridge. The .50 BMG, while firing a skinnier bullet, has more energy. The largest rifle made for sporting use was probably the .700 Nitro Express, however, military anti-tank rifles (fired from the shoulder) have been as large as 20 mm- about .80 caliber. Some muzzle loading black powder weapons fired a 1 inch, or 1.00 caliber bullet. The king of the BIG bore is probably the Paradox- these were part rifle, part shotgun- that were measured in gauge rather than caliber. The largest, the 2 bore, fired a slug about 40 mm in diameter- or 1.600 caliber.
.22-.50
Caliber (or calibre) is a measurement of the inside diameter of the barrel, and is also used to refer to the particular cartridge fired by a given gun. A .45 caliber gun fires a bullet that is ROUGHLY .45 inches in diameter. A 9mm uses a bullet that is ABOUT 9mm in diameter.
You need to define "highest caliber". If you mean the diameter of a bullet, there have been dozens of VERY large caliber rifles, about an inch in diameter- but they are very scarce. One of the more common (relatively speaking- they are still pretty scarce) largest calibers is the .700 Nitro Express- which would leave the .600 Nitro Express as second highest. Cartridge about the size of a small hotdog.
hp 802 small cartridge contained 2.5-3 ml, and large cartridge contained about 4ml.
Properly written as .10 caliber (notice the decimal ?) a .10 caliber firearm would fire a VERY tiny bullet- 1/10th of an inch in diameter- less than half the size of a .22 caliber. However, since very few firms have ever made a cartridge that tiny, you MAY be referring to a 10 GAUGE shotgun- which is VERY large- about 3/4ths of an inch in diameter. With shotguns, the smaller the gauge, the bigger the shell.
It depends on what kind you're referring to. It can range from a few cents for a .22 (although, it's unlikely that you will find single bullets for sale anywhere) up to several dollars for a large caliber bullet.
I'm not real familiar with the 38-40, but based on what I looked up, I'm going to say no. The 38-40 cartridge uses a .40 caliber bullet, which means the chamber in a 38-40 handgun would be too large in diameter to properly/safely hold the .38 special.
NO. The case is too large to enter a 22LR chamber. If chambered in a .22 magnum, you will be firing a .17 caliber bullet out of a .223 barrel, with no accuracy at all, and splitting the cartridge case.