A reaction that absorbs heat.
C(s) + H2O(g) CO(g) + H2(g), ΔH = +115 kJ/mol
N2(g) + O2(g) 2NO(g), ΔH = +192.5 kJ/mol
When pressure decreases, the equilibrium will shift to the side with the least moles of gas. Like in the case of dissociation of ammonia, if the pressure is decreased to keep Kp constant, number of moles of gas should increase.
This is False!!! According to LeChatlier's Principle, increasing the temperature is a strees on the equilibrium. To relieve that stress the reaction will shift producing more of the substances on the side of the reaction that absorbs heat energy.
If the temperature is less than the temoerature requ ired for reaction to proceed,higher co slip will result.Decreasing the inlet temperature to optimum inlet temperature will result in more conversion.
Increasing temperature affects a reaction in two ways: 1) at higher temperatures the molecules are moving around faster and collisions and reactions are more frequent, so the reaction - both forward and reverse - speed up. 2) at higher temperatures, the equilibrium state will shift. In some cases it will shift the equilibrium towards the product. In other cases, it will shift it back towards the reactants.
You can make it shift, by Le Chatliers principle. Or. By Reaction Quotient method and comparing it against the Equilibrium constant.
The gear ration changes at each shift. Read this: http://science.howstuffworks.com/gear-ratio.htm
It depends if the reaction is exothermic or endothermic. For example: If the reaction requires energy (endothermic), then energy (i.e. 100kJ) will be a reactant on the left-hand side. Then, use Le Chatelier's Principle from there. If you increase the temperature of the system in equilibrium, it will shift towards the product/right-hand side. If you decrease the temperature of the system, it will shift towards the reactants/left-hand side.
endothermic reaction. because as you may have seen, high temperatures are required to speed up the reaction. this is because, since the reaction in endothermic, high temperatures would cause the equilibrium to shift forward to decrease the temperature thus leading to the formation of more esters thereby speeding up the reaction (le chatelier's principle).
Endothermic reaction
This is False!!! According to LeChatlier's Principle, increasing the temperature is a strees on the equilibrium. To relieve that stress the reaction will shift producing more of the substances on the side of the reaction that absorbs heat energy.
The reverse reaction is not always endothermic or exothermic, the reverse reaction is the opposite of whatever the initial reaction is, so if the reaction is endothermic, the reverse reaction is exothermic and vise versa.
If the temperature is less than the temoerature requ ired for reaction to proceed,higher co slip will result.Decreasing the inlet temperature to optimum inlet temperature will result in more conversion.
evaporation This is the chemical reaction for water heating: H2O (liquid) + heat ---> H20 (gas) This is an endothermic reaction, meaning that by adding heat, it will shift the reaction towards the products, thus making more H2O gas. It is simply a phase change.
The enthalpy of the reaction.
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Increasing temperature affects a reaction in two ways: 1) at higher temperatures the molecules are moving around faster and collisions and reactions are more frequent, so the reaction - both forward and reverse - speed up. 2) at higher temperatures, the equilibrium state will shift. In some cases it will shift the equilibrium towards the product. In other cases, it will shift it back towards the reactants.
Increasing temperature affects a reaction in two ways: 1) at higher temperatures the molecules are moving around faster and collisions and reactions are more frequent, so the reaction - both forward and reverse - speed up. 2) at higher temperatures, the equilibrium state will shift. In some cases it will shift the equilibrium towards the product. In other cases, it will shift it back towards the reactants.
It depends on the order of the reaction. If it is zero order, decreasing the reactant concentration will have NO effect on the rate. If it is 1st or 2nd order (or more), then decreasing the concentration will DECREASE the reaction rate.