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The weight of the barge plus cargo will equal the weight of the water it displaces. If the barge sinks to a depth of 4' then the volume of barge under water is 4 x 25 x 100 = 10,000 cf. This will also be the volume of water displaced. Water weighs 62.4 lbs per cf so 10,000 cf weighs 624000 lbs. This will be the cargo weight plus the weight of the barge. No way to separate the two weights, but the barge weight is probably a small portion of the total.

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Q: What weight of cargo could a barge carry if it was 100ft long x 25 ft wide x 10 ft high and it was lowered 4 ft into the water?
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