charge will be suspended it will not have any direction
But you do feel gravitational force. Your body has weight, doesn't it? Your arms have weight and you feel them being pulled down? If you let go of your arms, they move down? What you feel is the force required to oppose the force of gravity. Newton's Third law says that, for every force, there is an equal and opposite force. Your muscles impose a force holding your arms up. You feel this as effort, i.e. force. As far as electrostatic force, its the same concept...
Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.
The gravitational force IS the centripetal force in this case.
Charge is a Scalar Quantity as it only have Magnitude not Direction.Like in 10 Coulomb of Charge, it has 10 as magnitude and Coulomb as Unit. But this is not showing any information which tell us that it is in a particular direction.
"Normal" forces push up on a still car. In this case, normal forces are equal in magnitude but opposite in direction to the gravitational forces pushing down on the still car.
Only if they have equal masses (in the case of gravitational orbits), or equal electric charges (in the case of electrostatic orbits).
Electrostatic equilibrium simply means that no net force is acting on the charged particle, and it doesn't accelerate, ie it's a charge fixed in space
Yes, electrostatic force obeys Newton's third law; equal and opposite. Example 1: the electrostatic force on a single Na+ due to a single Cl- in a crystal of NaCl is the same magnitude but opposite in direction. Example 2: the electrostatic force on a single Na+ due to a single SO4^2- in a solution of Na2SO4 is the same magnitude as the force on the SO4^2- but in the opposite direction.
Gravitational potential energy is not equal to kinetic energy:MGY doesn't always equal (1/2)mv2. This holds true in the CHANGE of gravitational potential energy being equal to the CHANGE in kinetic energy because of the Law of Conservation of Energy, Mass, and Charge.
They are equal in magnitude but opposite in charge.
The answer to that one is an unqualified 'YES'. There is a pair of equal gravitational forces, one in each direction, between every two specks of mass in the universe, all the time.
The force the rocket uses is stronger or equal to the rocket's mass, so it can push it in the opposite direction of the Earth's gravitational pull.
Even if it is the electrostatic force or gravitational force, I have F=constant*(mass or charge 1)(mass or charge 2)/radius^2. If the distance is tripled, then r is equal to 3. Let us say that mass or charge 1 and mass or charge 2 and the constant is 1. Forgetting the units, F=(1*1*1)/(3^2) which equals F=1/9. Therefore, the force of attraction will be reduced to 1/9 of its original strength if the distance between the two is tripled.
F=mg (it says in the task), where m is mass of electron and g is the gravitational acc. F=kQ2/r2 , where Q is the charge, r is the distance, k is constant Deriving, the expression for distance is: r2=kQ2/mg you should get that r = 5m
But you do feel gravitational force. Your body has weight, doesn't it? Your arms have weight and you feel them being pulled down? If you let go of your arms, they move down? What you feel is the force required to oppose the force of gravity. Newton's Third law says that, for every force, there is an equal and opposite force. Your muscles impose a force holding your arms up. You feel this as effort, i.e. force. As far as electrostatic force, its the same concept...
An electrostatic force attracts oppositely charged particles.
Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.Yes - gravitational potential energy is equal to mass x gravity x height.