We would not be able to move so I don't think the gravity will be affected
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
g
When the earth stops spinnig there will be no centripetal acceleration and will be no gravity.therefore g=0. since w=mg w=m(0) w=o there will be no weight of a body if earth sudddenly stops spinning
NO.... It stops at G
As you move deeper into the Earth, the value of acceleration due to gravity (g) decreases slightly. This is because the mass directly below you is pulling you down, while the mass above you is also pulling you up. The net effect of these opposing forces is a slight decrease in the value of g as you move deeper into the Earth.
Ricardo Caballero G. has written: 'Fear of sudden stops'
The equatorial surface gravity of Saturn is 1.065 g. Whereas that of earth is 0.99732 g. So yes it is. Comment: Or is it? NASA have a data page showing Saturn's gravity as about 0.92 times Earth's gravity. That's because they take into account the effect of the planet's rotation. This is a question with two different correct answers, depending on the definitions used. That's annoying. (Incidentally, the value 0.99732 g for Earth must take into account Earth's rotation, otherwise it would surely be 1.00000 g. The effect of rotation is far less for Earth, of course.)
G-I- Joe - 1985 Cobra Stops the World 1-9 was released on: USA: 26 September 1985
The schwarzschild radius of the Earth is about 8.7 x 10 to the negative 3m. The schwarzschild radius is the radis of a sphere that is around a non-rotating blackhole. You find the Rs, or radis, by multiplying the gravitational constant(G), the mass(M), and two. You divide this by the speed of light(c) squared.
g, the force of the Earth's gravitational attraction, is not a constant.
nothin g