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A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2
Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
The time that it "takes" is the period.
A pendulum whose period is precisely two seconds, one second for a swing forward and one second for a swing back, has a length of 0.994 m or 39.1 inches.
If the length of the second pendulum of the earth is about 1 meter, the length of the second pendulum should be between 0.3 and 0.5 meters.
Second's pendulum is the one which has 2 second as its Time period.
25m
1.0002m
This pendulum has a length of 0.45 meters. On the surface of the moon, its period would be 3.31 seconds where g = 1.62m/s^2
Suppose that a pendulum has a period of 1.5 seconds. How long does it take to make a complete back and forth vibration? Is this 1.5 second period pendulum longer or shorter in length than a 1 second period pendulum?
100 cms for the second's pendulum
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
The time that it "takes" is the period.
The period is 1 second.
Period of a pendulum (T) in Seconds is: T = 2 * PI * (L/g)1/2 L = Length of Pendulum in Meters g = Acceleration due to gravity = 9.81 m/s2 PI = 3.14 The period is independent of the mass or travel (angle) of the pendulum. The frequency (f) of a pendulum in Hertz is the inverse of the Period. f = 1/T