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Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.
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What pendulum lenght in Nairobi would have a time period of one second?
A pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of one second. This is because the acceleration due to gravity in Nairobi is approximately 9.81 m/s^2.
What is the length of second pendelum?
The length of a pendulum affects its period of oscillation, but to determine the length of a specific pendulum, you would need to measure it. The formula for the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
What will be the time period of occillatione length of the second pendulum is one third?
The time period of a pendulum is determined by its length and gravitational acceleration. If the length of the second pendulum is one third of the original pendulum, its time period would be shorter since the time period is directly proportional to the square root of the length.
What happens to the period of a pendulum if you increase its mass?
Increasing the mass of a pendulum would not change the period of its oscillation. The period of a pendulum only depends on the length of the pendulum and the acceleration due to gravity, but not the mass of the pendulum bob.
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
What pendulum lenght in Nairobi would have a time period of one second?
A pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of one second. This is because the acceleration due to gravity in Nairobi is approximately 9.81 m/s^2.
Does the length of pendulum affect the period of vibration?
Yes. Given a constant for gravity, the period of the pendulum is a function of it's length to the center of mass. In a higher gravity, the period would be shorter for the same length of pendulum.
What would be the period of a pendulum with the length of 10 meters?
For a simple pendulum: Period = 6.3437 (rounded) seconds
What is the length of second pendelum?
The length of a pendulum affects its period of oscillation, but to determine the length of a specific pendulum, you would need to measure it. The formula for the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
What will be the time period of occillatione length of the second pendulum is one third?
The time period of a pendulum is determined by its length and gravitational acceleration. If the length of the second pendulum is one third of the original pendulum, its time period would be shorter since the time period is directly proportional to the square root of the length.
What happens to the period of a pendulum if you increase its mass?
Increasing the mass of a pendulum would not change the period of its oscillation. The period of a pendulum only depends on the length of the pendulum and the acceleration due to gravity, but not the mass of the pendulum bob.
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
Time period of simple pendulum is three seconds the same pendulum taken at the moon - what will be its new time period?
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
What increases the period of a pendulum?
Making the length of the pendulum longer. Also, reducing gravitation (that is, using the pendulum on a low-gravity world would also increase the period).
What is the period of this pendulum if Its length is doubled?
The period of a pendulum is given by the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. If the length is doubled, the new period would be T' = 2π√(2L/g), which simplifies to T' = √2 * T. So, doubling the length of the pendulum increases the period by a factor of √2.
Does the force gravity speed up the period of a pendulum?
No, the force of gravity does not affect the period of a pendulum. The period of a pendulum is determined by the length of the pendulum and the acceleration due to gravity. Changing the force of gravity would not change the period as long as the length of the pendulum remains constant.
A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2π√(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.
