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Since the equation of an inductor is ...

di/dt = v/L

... then increasing the current in the RL network would cause a back-emf in the inductor that would initially seem to oppose the series current.

More correctly, the question should ask "what if the voltage were increased?"; and the answer is that the rate of change of current in the inductor would increase, but the current would not initially change.

This is the case for a series RL.

For a parallel RL, increasing the current would initially show up as an increase the the current through the R, increasing voltage in the L, with the same effect as noted above.

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Q: What will happen if increase the input current of an inductor in RL circuit?
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When you add a resistor to a series circuit what will happen to the total current?

increase.


Why does a switch spark when disconnecting a coil carrying high dc current?

An inductor resists a change in current. If you have a steady state current going through an inductor and you attempt to suddenly increase the current, the inductor will nearly instantaneously present a higher resistance so that the current does not immediately change. Its resistance, then, will start to decrease as the current ramps up to the new value. Similarly, if you have a steady state current going through an inductor and you attempt to suddenly decrease the current, the inductor will nearly instantaneously present a lower resistance so that the current does not immediately change. Its resistance, then, will start to increase as the current ramps down to the new value. That's all just background information so you can understand what an inductor is. If you have a steady state current going through an inductor and you attempt to suddenly decrease the current to zero by opening the circuit, the inductor will respond by attempting to maintain the current, but that current has nowhere to go. This creates a large negative voltage spike across the inductor. Think about it. Ohm's law says that voltage is current times resistance. You have some current; you have infinite resistance; therefore you must have infinite voltage. In fact, a theoretical pure inductor will do exactly that - generate an infinitely large negative voltage spike. That does not happen in practice, but it is very common to see transients of several hundred or thousand volts. This is why you need to have some kind of suppression circuit in place - otherwise that transient will go back and blow out whatever circuit is driving it.


If the resistance increases what will happen to voltage and current?

If you have a simple circuit. For eg: One voltage source and one resistor, then the voltage of the circuit will always remain the same, the current however will decrease following Ohms' Law V=I*R. If we have a current source instead of a voltage source, we are forcing the current to be a certain value so if we increase the resistor value the current will remain the same but the voltage will increase.


What will happen if more bulbs are added to a circuit with one cell?

YESAnswerNot necessarily. The current depends on the potential difference and the load resistance. If you connect cells in parallel, you do not effect its voltage or the load, so the current is unaffected (although the battery's current 'capacity' will increase). If you connect the cells in series, then you will increase the voltage and the current will increase.


What will happen if you pass ac current passes through a inductor?

magnetic flux will be induced its use to rotate the shaft or given some force

Related questions

What does a inductor do in a circuit?

DC current has no effect on the inductor(can be considered as a short circuit) as the current does not change in a DC supply voltage this one just produces a magnetic field which remains constant , as the magnetic field is not varying no emf is induced in the circuit , so literally it has no effect on the circuit when the supply is of DC voltage.when an alternating current is set up in a circuit , the Alternating current brings a magnetic field in the inductor which is variable (since the current is varying...) this variable magnetic field induces an emf in the circuit (back emf) which opposes the cause that is producing the change (lenz's law)explanation consider a circuit with an inductor connected to an AC voltageduring the positive half cycle when the voltage increases the current also increases in the circuit [take the current direction as clockwise] this causes a variable increasing magnetic field in the inductor , this magnetic field in turn induces current in the circuit which is opposing the increase in the current flow from the original source, the inverse happen during the decreasing half of the half of the positive cycle , here the induced current adds up with the decreasing current opposing the cause that produced this back current (cause :- decrease in current changes the magnetic field so the induced current is produced ..... it is opposing the change because :- the induced current either decreases the increasing current or increases the decreasing current )


When you add a resistor to a series circuit what will happen to the total current?

increase.


Why does a switch spark when disconnecting a coil carrying high dc current?

An inductor resists a change in current. If you have a steady state current going through an inductor and you attempt to suddenly increase the current, the inductor will nearly instantaneously present a higher resistance so that the current does not immediately change. Its resistance, then, will start to decrease as the current ramps up to the new value. Similarly, if you have a steady state current going through an inductor and you attempt to suddenly decrease the current, the inductor will nearly instantaneously present a lower resistance so that the current does not immediately change. Its resistance, then, will start to increase as the current ramps down to the new value. That's all just background information so you can understand what an inductor is. If you have a steady state current going through an inductor and you attempt to suddenly decrease the current to zero by opening the circuit, the inductor will respond by attempting to maintain the current, but that current has nowhere to go. This creates a large negative voltage spike across the inductor. Think about it. Ohm's law says that voltage is current times resistance. You have some current; you have infinite resistance; therefore you must have infinite voltage. In fact, a theoretical pure inductor will do exactly that - generate an infinitely large negative voltage spike. That does not happen in practice, but it is very common to see transients of several hundred or thousand volts. This is why you need to have some kind of suppression circuit in place - otherwise that transient will go back and blow out whatever circuit is driving it.


What do inductors do in a circuit?

DC current has no effect on the inductor(can be considered as a short circuit) as the current does not change in a DC supply voltage this one just produces a magnetic field which remains constant , as the magnetic field is not varying no emf is induced in the circuit , so literally it has no effect on the circuit when the supply is of DC voltage.when an alternating current is set up in a circuit , the Alternating current brings a magnetic field in the inductor which is variable (since the current is varying...) this variable magnetic field induces an emf in the circuit (back emf) which opposes the cause that is producing the change (lenz's law)explanation consider a circuit with an inductor connected to an AC voltageduring the positive half cycle when the voltage increases the current also increases in the circuit [take the current direction as clockwise] this causes a variable increasing magnetic field in the inductor , this magnetic field in turn induces current in the circuit which is opposing the increase in the current flow from the original source, the inverse happen during the decreasing half of the half of the positive cycle , here the induced current adds up with the decreasing current opposing the cause that produced this back current (cause :- decrease in current changes the magnetic field so the induced current is produced ..... it is opposing the change because :- the induced current either decreases the increasing current or increases the decreasing current )


What happen when there is a break in the path circuit?

Current through that part of the circuit will stop.


If the resistance increases what will happen to voltage and current?

If you have a simple circuit. For eg: One voltage source and one resistor, then the voltage of the circuit will always remain the same, the current however will decrease following Ohms' Law V=I*R. If we have a current source instead of a voltage source, we are forcing the current to be a certain value so if we increase the resistor value the current will remain the same but the voltage will increase.


What will happen if more bulbs are added to a circuit with one cell?

YESAnswerNot necessarily. The current depends on the potential difference and the load resistance. If you connect cells in parallel, you do not effect its voltage or the load, so the current is unaffected (although the battery's current 'capacity' will increase). If you connect the cells in series, then you will increase the voltage and the current will increase.


What will happen to the circuit if the bulb if removed from its holder?

Nothing will happen to circuit..... as usual the circuit would be supplying 220v(if india) and certain current...but there is no bulb to consume power...


When a switch in an electrical circuit is turned off what will happen?

Closing a switch in an electrical circuit will complete the circuit. The supply voltage will then be applied to that circuit, and current will flow through that circuit.


What will happen if you pass ac current passes through a inductor?

magnetic flux will be induced its use to rotate the shaft or given some force


If the resistance in a circuit remains what will happen to the current if the voltage increases?

The current will also increase. This can be proved by using ohms law, V=IR --> I=V/R, as the resistance is constant the R can be replaced by the number 1 therefore I=V/1 or I=V, hence if the voltage increases the current must also increase.


What happen to the voltage when the collector current increases in a biased circuit?

it dies