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If a rheostat is connected in parallel with a light bulb, the setting of the rheostat should have no effect on the performance of the light bulb, as long as the power supply is able to maintain its output voltage and deliver the current demanded by their parallel combination.
Adding additional lamps has no effect on the supply voltage supplied to you home. If the lamps are connected in series, then the sum of voltage-drops appearing across each lamp will equal the supply voltage. If the lamps are connected in parallel, then the voltage across each lamp will equal the supply voltage.
The circuit voltage or the resistance of the individual bulb is needed to answer this question. Divide the total power (400 W) by the supply voltage.
This bulb is very likely to be burn out since the 440 supply voltage is very higher than it's rated voltage.
1.) In series if 1 light bulb goes out they all do.2.) For each appliance to operate at its rated power, it must be subject to its rated voltage which corresponds to the value of the supply voltage. A parallel connection ensures that each branch is subject to the same (supply) voltage.
If a rheostat is connected in parallel with a light bulb, the setting of the rheostat should have no effect on the performance of the light bulb, as long as the power supply is able to maintain its output voltage and deliver the current demanded by their parallel combination.
In a series circuit the total voltage is the sum of the voltage drops across all the component in series. When the voltage drops across each the individual components are added up, they will equal the supply (or applied) voltage.
Yes it can be transformed from one voltage to the other.
The rf output voltage should be proportional to the signal voltage in AM. A change in the DC supply voltage should also cause a proportional change to the rf output voltage.
By using a voltage divider, that is two resistors of the same value in series across the DC supply. Half of the supply voltage will be at the point where the two resistors is connected. But how much wattage of those resistors is also an issue.
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Adding additional lamps has no effect on the supply voltage supplied to you home. If the lamps are connected in series, then the sum of voltage-drops appearing across each lamp will equal the supply voltage. If the lamps are connected in parallel, then the voltage across each lamp will equal the supply voltage.
The circuit voltage or the resistance of the individual bulb is needed to answer this question. Divide the total power (400 W) by the supply voltage.
If supply decreases the prices will go up and quantity will go down and surely total surplus will be reduced.
Divide the number of lamps into the value of the supply voltage, and that will tell you the voltage drop appearing across each lamp. Bear in mind that if one of the lamps should be removed, the full supply voltage will then appear across the empty lamp holder.
The circuit by itself doesn't determine the voltage of the power supply. If there's some additional requirement that goes along with the circuit, such as "The current through the circuit must be XYZ amperes.", or "The voltage across the third component from the north end of the circuit shall be ABC volts,", then that requirement would dictate the power supply voltage. But in order to calculate it, you'd need the knowledge of every component in the series circuit.
Lamps will only operate at their rated power when subjected to their rated voltage -which is why you will see both figures shown on the glass envelope (e.g. 60 W / 230 V or 60 W / 120 V, etc.). If you connect lamps in parallel, because each branch is subject to the same voltage (i.e. the supply voltage), each lamp has the same voltage applied and will operate at its rated power. If you connect lamps in series, the supply voltage will distribute itself as a series of voltage drops where the sum of the voltage drops will equal the supply voltage. So none of the lamps is subject to its rated voltage, so none will operate at its rated power -i.e. they will be dim!