This is clearly a case of motion under constant acceleration(deceleration).
The equation you need to use would be:
(1) S = vo - 0.5 * a * t2, where:
S - distance,
vo - starting velocity,
a - acceleration,
t - time.
Acceleration can be easily found from
(2) a = F / m, where:
F - force(here: 2000 N),
m - mass(of the car: 1000 kg).
Time it takes for a car to stop is a time it takes for its starting velocity to drop to 0 with a constant rate of deceleration(a):
(3) t = vo / a
Substituting (2) and (3) into (1), we get:
S = vo - 0.5 * (F / m) * vo2 / (F / m)2, which simplifies to:
(4) S = vo - 0.5 * mvo2 / F.
Now, after substituting numerical values, we get our answer:
S = 10[m/s] - 0.5 * 1000[kg] * 100[m2/s2] / 2000 N =
= 25[m]
Note: 1[N] = 1[kg * m / s2], which makes above equation with units check out.
1000kg proof 1000kg = 1000000 g
Both the same. 1000kg = 1 metric tonne.
1000kg
1 tonne = 1000kg 1.4 tonnes = 1.4 x 1000kg = 1400kg
the jeepney of mass 2000kg is more difficult to stop than the tricycle of mass 1000kg because the force applied to the former is greater than the latter. thus, a heavier object requiring greater force to move needs greater force to stop it or interfere its linear movement.
It is 1000kg
1000kg
1 metric tonne = 1000kg, so 1880kg/1000kg/1 tonne = 1.88 tonnes
liter
A metric ton is 1000kg.
1 Tonne
1000kg = 1tonne