What wins in Texas holdem a pair of kings and a pair of queens or a pair of two and a pair aces?
A pair of Aces & Deuces (Deuces = Two's) will win over a pair of Kings and Queens.
A poker hand consist out of 5 cards. The highest card(s) win of course the hand.
In this case I'm going to give you an example. Since there is no 5'th card I'll use X for it.
A pair of Aces & Deuces will look like AA22X. In this case the highest pair (or valid combination of more then 2 cards) is the Aces.
The pair of Kings & Queens looks like KKQQX. As you can see here, the highest pair (or valid combination of more then 2 cards) are the Kings.
Because the Aces are of course higher then the Kings, the hand AA22X (or Aces and Deuces) win the hand.
Two pair works like this, the higher pair determines who is the winner. Suppose I have two pair Aces and fives, that means I beat all two pair that have kings as the higher pair, and queens etc. So Aces and fives beats Kings and queens. Now, if there is tie then the second pair comes in, so Aces and fives loses to Aces and sevens.
There a many good hands in Texas Holdem, such as, Three of a kind (when you get dealt your two cards, they are the same numbers on both, and there is a card on the table with the same number as the cards in your hand), the Straight (five consecutive cards- Aces may be used before a two or after a King), the Flush (five cards of the same suit), Full House (three of a…
"Bad beat" is just a colloquial expression referring to having a very strong hand and losing to an unlikely, but possible, better hand. Such as if a player were to lose with four aces in holdem to a player with a straight flush. That means the bad beats have no formal place in any rules of procedure and are thus unlikely mentioned in any contest or casino rules (which I assume you meant instead of…
3 pair does not constitute a legal hand in poker. Therefore, 3 of a kind is better. You play your two highest pairs if you so happen to have 3 pairs in play! For instance in Texas Hold em: You have a Pair of Queens, other dude has Jack ten. The flop comes out and its Jack 10 Ace then turn is ACE and River is 3. The guy who had 2 pair Jacks and…
3Q and 2 nines aka Queens full of Nines. Basically a full house is: 3 Cards + 2 cards. The full house rank is based upon the 3 cards; the higher the better. Lets give an example: AAA99 = Aces full of 9s 999AA = Nines full of Aces The aces full is better, and another example (If both players have Sixes full of X; then the X comes in to play; kind of like…
How many 5 card poker hands consisting of 2 aces and 3 kings are possible with an ordinary 52 card deck?
It is a way to use step responses to indicate the number of aces/kings in responders hand. Aces = 2 controls, kings = 1 control. Typically 2D = 0-1 controls, 2H = 2 controls, 2S = 3 controls, specifically an ace and king, 2NT = 3 controls, specifically 3 kings, 3C = 4 controls, 3D = 5 controls, etc.
When the deck is full, this probability is 4/52 (the probability of getting one of 4 aces) times 16/51 (the probability of getting one of 16 kings, queens, jacks, or tens) times 2 (the number of orders in which you could get these cards: ace first, or ace second). This comes out to 32/663, or about 4.83%. Of course, this probability changes as the game progresses: it decreases when any of the tens, jacks, queens…
The highest valued "hand" could mean several things but for a final 5 card hand the best cards are the very rare royal flush. That is 10, jack, queen, king, ace, all of the same suit (suits are valued equally). For Texas holdem (one of the most common forms of poker) the highest valued pocket cards to have are two aces.
52, or 54 including jokers. 52 + 2 jokers ANSWER 52/54 : correct, of course, for what is commonly called a "bridge" or a "poker" deck. A "pinochle" deck, on the other hand, has 48 cards: doubles of 9s, 10s, jacks, queens, kings, and aces, in each of the four suits. Jokers, which are not used in play, would add extra cards.
Double aces is a pair, it would be beaten by a three of a kind, unless someone else has a pair of aces also, in which case the next highest card in the hand would win. For example: between the hands of A, A, 10, 6, 2 and A, A, 7, 4, 3 the 10 would win. a pair of 1,2,3,4,5,6,7,8,9,10,jack,queen, or king would beat a pair of aces.
No, Let's say that Ace is high and that pictured cards are numbered for a second: 2-2 3-3 4-4 5-5 6-6 7-7 8-8 9-9 10-10 Jack-11 Queen-12 King-13 Ace-14 THREE SEVENS AND TWO ACES: (3x7) + (2x14) = (21+28) = 49 THREE KINGS AND TWO FIVES (3x13) + (2x5) = (39+10) = 49 Yes, they come to the same total HOWEVER it would make the same. Does anyone have a "kicker" - A card in…
There are four cards that are greater than a 10 in a ten of cards. Jacks, Queens, Kings, and Aces. There are 4 colors, Spades, Hearts, Diamonds, and Clubs. Hence there are 16 cards that are greater than 10. Any one of the 16 is greater than 10. So the probability that a card you pick is greater than 10 is 16/52 = 4/13
No, the higher ranking pairs in each hand have priority and are compared first and a pair of Aces beats a pair of Kings. The value of the lower pair is only relevant if the higher pairs in each hand are the same, for example KQ v K7. In this example the lower ranking pairs in each hand would be compared and because a Queen is higher than a seven, KQ beats K7.