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What would be the acceleration of a body if its velocity time graph is a line parallel to the time axis?
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What would the graph look like on a position verse time plot with constant acceleration?
If the constant acceleration is positive, the graph would be an exponential (x2) graph. If there is constant acceleration, then velocity is always increasing, making the position change at an ever increasing rate.
How would a graph look if the speed is constant?
That would depend on the type of axes. If it is an acceleration vs. time graph, then there would be a continual reading of 0m/s/s acceleration, and the graph would be a straight line indicating 0m/s/s at all times. If it is a velocity vs time graph, then there would be a constant value of velocity at all times. If it is a displacement vs time graph, there would be a straight, continuously increasing line.
What does the slope of a line on a velocity vs time graph represent?
The slope of the line of a speed-versus-time graph will give you acceleration. Remember that acceleration may be positive or negative, and in some cases, acceleration may be positive when speed remains the same.1 If the speed-time curve is linear or piecewise linear2, acceleration is, as stated above, merely the slope of the line segment. If, however, the graph is a smooth curve, then changing acceleration is represented. In other words, the rate of change of velocity -- delta-V over delta-T -- is not a constant. In that case, the slope of the line segment tangent to the curve at any given point is the acceleration at that point. Note 1: There is a discussion comment on this point.Note 2: See the web link for an example of a graph that is piecewise linear.
What does the slope of a tangent to the curve of a velocity-time graph measure?
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
What are the advantages of velocity time graph?
Normally a position-time graph is actually a distance-time graph where the distance of an object is measured from a fixed point called the origin. The slope (gradient) of the graph is the radial velocity - or the component of the velocity in the radial direction - of the object. That is, the component of the object's velocity in the direction towards or away from the origin. Such a graph cannot be used to measure the component of the velocity at right angles to the radial direction. In particular, an object going around in a circle would appear t have no velocity since its distance from the origin remains constant.
What does the area under the acceleration-time graph represent?
its the velocity
How is instantaneous acceleration related to a velocity-time graph?
Acceleration is the derivative of velocity (a=dv/dt). If you are not familiar with calculus then it would be sufficient to say that the slope of the line tangent to the graph, only touches at one point, is equal to the instantaneous acceleration.
What would the graph look like on a position verse time plot with constant acceleration?
If the constant acceleration is positive, the graph would be an exponential (x2) graph. If there is constant acceleration, then velocity is always increasing, making the position change at an ever increasing rate.
How would you obtain the acceleration of an object from a velocity time graph?
The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.
How would a graph of negative and positive acceleration differ?
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).
Is it possible of a body to have its velocity and acceleration pointing in opposite direction plot a velocity-time graph if yes?
Yes, it is possible. For example, if you through an object up, its velocity would initially be in the "up" direction, but its acceleration would be in the "down" direction.
What is the difference between a velocity time graph and a position time graph?
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
How would a graph look if the speed is constant?
That would depend on the type of axes. If it is an acceleration vs. time graph, then there would be a continual reading of 0m/s/s acceleration, and the graph would be a straight line indicating 0m/s/s at all times. If it is a velocity vs time graph, then there would be a constant value of velocity at all times. If it is a displacement vs time graph, there would be a straight, continuously increasing line.
What would be the nature of the motion if the force-time graph is parallel to x-axis?
constant positive acceleration
What graph are used to analyze the motionof an accelerating objects?
On a accelerating body, Velocity and distance of an object are effected. For a graph plotted with Acceleration to Time, it directly gives the acceleration at any given instant. For a graph plotted with Velocity versus Time. The Slope at any instant would give the Acceleration. Or given the time frame, say A to B. Acceleration can be found out by subtracting velocity at A from velocity at B divided by the time frame A to B.
What does the slope of a line on a velocity vs time graph represent?
The slope of the line of a speed-versus-time graph will give you acceleration. Remember that acceleration may be positive or negative, and in some cases, acceleration may be positive when speed remains the same.1 If the speed-time curve is linear or piecewise linear2, acceleration is, as stated above, merely the slope of the line segment. If, however, the graph is a smooth curve, then changing acceleration is represented. In other words, the rate of change of velocity -- delta-V over delta-T -- is not a constant. In that case, the slope of the line segment tangent to the curve at any given point is the acceleration at that point. Note 1: There is a discussion comment on this point.Note 2: See the web link for an example of a graph that is piecewise linear.
What does the slope of a tangent to the curve of a velocity-time graph measure?
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
