The formula for the compound between Lithium and Sulfur is Li2S because Lithium has a +1 charge while Sulfur has a -2. So for it to be stable, there needs to be two Lithium atoms attached to one Sulfer.
The chemical formula for the compound formed by lithium and oxygen is Li2O, and is named lithium oxide.
The chemical formula for lithium bromide is LiBr.
Lithium sulfide is Li2S.
The compound formed from lithium and oxygen is lithium oxide, with the formula unit Li2O.
Lithium fluoride is the compound formed as a result of this reaction: LiF is the formula.
Lithium sulfate - Li2SO4 Lithium sulphide - Li2S
lithium chloride LiCl
Lithium and fluorine react together to form lithium fluoride which is an ionic compound.
Li2CO3: Lithium is a monovalent cation and carbonate is a divalent anion, so that two lithium ions are required for each carbonate ion.
The ionic compound formed between magnesium and chlorine has the formula MgCl2.
A formula for a compound formed between sodium cations and sulfate anions is Na2SO4.
Lithium ion is Li+ and a bromine ion (called a bromide ion) is Br- and the compound formed from them would be LiBr.
The chemical formula for the compound formed between potassium and iodine is KI (potassium iodide).
The chemical formula for the compound formed between rubidium and oxygen is rubidium oxide - Rb2O.
Lithium will donate 1 electron to Flourine to help Flourine reach an octect... LiF.
The compound formed between rubidium and chlorine has the formula RbCl.
This compound doesn't exist.
The compound formed between sodium and selenium is named "sodium selenide" and has the formula Na2Se.
The compound formed between aluminum and oxygen is called aluminum oxide. It has a formula of Al2O3.
the correct formula for ionic compound between calcium and chlorine is CaCl2
The formula would be K2Se
The chemical formula for the compound formed between iron(III) and iodine is FeI3 (iron(iii) iodide).
The ionic compound potassium bromide, with formula KBr.
The chemical formula of the compound formed between cobalt (III) and the bromide ion it would be CoBr3, if this compound exist !
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