It's Pressure would rise.
boyle's law holds good in this case and the gas experiences decrease in volume....provided the gas is not in a container with fixed dimensions! its volume will decrease
The volume of the gas will decrease. the gas will also attempt to increase in temperature.
The volume of the gas will decrease. the gas will also attempt to increase in temperature.
When the temperature of a gas is increased while keeping the pressure constant, the speed of the gas molecules also increases. This is because the increase in temperature leads to a greater average kinetic energy of the gas molecules, causing them to move faster.
The temperature remain constant.
If the volume of the tank was effectivelly constant, and the tank was sealed to prevent gas escaping, the pressure of the gas would increase.
It increases.
Nothing if nothing evaporates.
When the temperature of a gas is increased at a constant pressure, its volume increases. When the temperature of a gas is devreased at constnt pressure, its volume decreases.
increased
This relies on 3 things. The Pressure, volume and temperature of a Gas is all related. If the pressure is kept the same and temperature increased. The Volume (of the container) must be increased. If the Volume (of the container) is kept constant and temperature is increased the Pressure will increase. A rough idea of what will happen can be worked out by, pV=cT Where p is the pressure, V is the volume of the container, c is a constant, T is the temperature.
This is consequence of a very common law which is known as Boyle's law.According to it when we give pressure to the gas at constant temperature the volume of gas decreases.The gas law formula is: pV/T=k; the volume is decreasing.