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A bag with a 2 percent solution is placed in a beaker that has a 10 percent solution is the solution in the bag hypotonic hypertonic or isotonic?
The solution in the bag is hypotonic compared to the solution in the beaker. This is because the bag has a lower concentration of solute (2%) compared to the beaker (10%), so water will tend to move into the bag to equalize the concentrations, causing the bag to swell.
What would happen to a plant cell if it was placed into a beaker containing a hypertonic solution?
The plant cell would lose water through osmosis and shrink in size due to the higher concentration of solutes in the hypertonic solution compared to the cell. This process is called plasmolysis, and it can lead to wilting of the plant cell.
Is the baggie or beaker hypertonic?
It depends on the concentration of solutes inside and outside the baggie or beaker. If the concentration of solutes is higher inside the baggie or beaker compared to the surrounding environment, then it is hypertonic. If the concentration is lower, then it is hypotonic.
What is happening to the red blood cell and cell in beaker?
In a beaker containing a solution, red blood cells can either swell or shrink depending on the solution’s tonicity. If the solution is hypotonic (lower solute concentration than inside the cells), water enters the cells, causing them to swell and potentially burst. Conversely, in a hypertonic solution (higher solute concentration), water exits the cells, leading to cell shrinkage. This movement of water across the cell membrane is driven by osmotic pressure.
What happens if a cell is placed in a beaker containing isotonic solution?
If a cell is placed in an isotonic solution, there will be no net movement of water across the cell membrane. The concentration of solutes inside and outside the cell will be equal, so the cell will maintain its normal shape and size as there is no osmotic pressure acting on it.
What the difference in the physical state of the carrot is as observed in the two beakers?
The physical state of the carrot in the first beaker appears firm and crunchy, while in the second beaker the carrot appears soft and limp. This difference is due to the first beaker containing water, which keeps the carrot hydrated and firm, whereas the second beaker contains a hypertonic solution that caused the carrot to lose water through osmosis, resulting in a limp texture.
A balloon permeable to water but not to glucose contains a 10 percent glucose solution A beaker contains a 5 percent glucose solution the solution in the balloon is what?
The balloon will contain a mixture of the 10% and 5% glucose solutions. Since water can pass through but not glucose, the glucose concentration inside the balloon will decrease over time as water moves from the lower concentration in the beaker to the higher concentration in the balloon through osmosis.
What would happen if you did an experiment in which the iodine solution was placed in the Baggie and the starch was in the beaker?
The iodine solution in the baggie would diffuse into the beaker containing the starch. The iodine molecules would interact with the starch molecules, resulting in the formation of a dark blue or black color, indicating the presence of a starch-iodine complex.
Is it important to dry a beaker before collecting a solution?
Yes, it is important to dry a beaker before collecting a solution as any remaining liquid in the beaker could dilute the solution being collected, affecting the concentration and accuracy of the solution. Drying the beaker also helps to ensure that the solution is not contaminated by any residual water or impurities from the beaker.
How do you test for monosaccarides?
You place Benedict's solution (blue solution) and the unknown substance (possibly containing monosaccarides) into a beaker and then heat it for approximately 5 minutes. If the substance contains monosaccarides, the solution will turn from blue to orange.
What you use a beaker for in science?
Containing liquids that are possibly harmful.
If A beaker contains 100 grams of 1.7 M NaCl and you transfer 50 grams what is the molarity of the solution in the beaker?
After transferring 50 grams of the 1.7 M NaCl solution to a new beaker, the final amount of NaCl in the original beaker will be 50 grams. To find the new molarity, you would first calculate the new moles of NaCl in the beaker, then divide by the total volume of the solution in liters. The molarity will be reduced in the original beaker due to the dilution from transferring a portion of the solution.
