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Since the reaction is first order with respect to H2, if the concentration of H2 were halved, the rate of the reaction would be halved. This can be seen by entering one for each value in the rate equation, then changing the value of [H2] to 1/2 while keeping the other values the same: The rate changes from 1 to 1/2.

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Q: What would happen to the rate of a reaction with rate law ratekNO2H2 if the concentratin of H2 were halved?
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