what a nice question ;
we would all die of too much heat and antoxication , stupid ! What the heck did you think ?
that we would die of old age ?
And i hope your not older than ten , 'cause that's how old i am .
jeez , the people these days i mean , seriously , tsk , tsk,
If a body's velocity is doubled, its momentum will also double, assuming that the mass remains constant. Momentum is directly proportional to velocity, so an increase in velocity will result in a corresponding increase in momentum.
If the temperature of a gas is doubled, the mean speed of the gas molecules will also double. This is because the average kinetic energy of the gas molecules is directly proportional to the temperature according to the kinetic theory of gases.
Twice the mass --> twice the kinetic energy.
The horizontal distance will be doubled.
If the mass of the object is doubled but the velocity remains the same, the kinetic energy of the object will also double. Kinetic energy is directly proportional to the mass of the object, so doubling the mass will result in a doubling of kinetic energy.
Thermal velocity occurs in situations where particles have random kinetic energy due to their temperature. This can happen in gases, liquids, or solids when the particles are vibrating or moving randomly. Thermal velocity is a measure of the average speed of the particles in a substance due to their thermal energy.
Assuming all other variables are kept the same, the volume would double.
Kinetic energy will increase by a factor of four. Kinetic energy is proportional to the square of velocity, so if velocity is doubled, kinetic energy increases by four times. Since mass remains the same, there is no impact on kinetic energy from changes in mass.
If the pressure is doubled and the temperature is reduced to half, according to Boyle’s Law, the volume of the gas will decrease by half. This is because pressure and volume are inversely proportional when temperature is constant.
It will increase
Hi there! Assuming that the deceleration (or negative acceleration, if you will) is constant and the same in both cases, you can use a special kinematic formula to solve the problem. The formula follows: (final velocity)^2 = (initial velocity)^2 + [ 2 * (deceleration) * (braking distance) ] Rearranged to our needs the formula reads: braking distance = [1/2] * -(initial velocity)^2 / (deceleration) * this equation assumes that the final velocity is zero If the initial speed were doubled then the general formula would read: braking distance = 2 * -(initial velocity)^2 / (deceleration) NOTICE that the two equations are the exact same except for the leading coefficients. 1/2 is assocaited with the braking distance of the normal velocity while 2 is assocated with the breaking distance of the doubled velocity. Since 2 is four times larger than 1/2, this leads us to the conclusion that the breaking distance for an object traveling at double a certain velocity would be 4x greater than the breaking distance of the object moving at the "regular" velocity.
Kinetic Energy = (1/2)*(mass)*(velocity)2 If you double the mass, then the kinetic energy will double If you double the velocity, the kinetic energy will increase by a factor of 4