Want this question answered?
If the volume of the tank was effectivelly constant, and the tank was sealed to prevent gas escaping, the pressure of the gas would increase.
The sound would sound "higher" to you, but not any louder or softer.
The temp of the gas would first rise, then drop. If the final volume of the gas is lower than the volume at the start, the temp will be higher than at the start. If the final volume is greater than at the start, then the temp of the gas will be lower than at the start.
No, the amount of a liquid is volume. Density is independent of volume.
This volume can be measured in millilitres.
The volume shrinks.
the volume would get bigger, and the solid itself would just get bigger.
Since the stroke volume increased then the cardiac out put would increase, pumping out more blood with the same amount of heart beats.
If the volume of the tank was effectivelly constant, and the tank was sealed to prevent gas escaping, the pressure of the gas would increase.
The sound would sound "higher" to you, but not any louder or softer.
idon't know sorry
the unit for volume, for a liquid would be oz(ounces) I believe..
The temp of the gas would first rise, then drop. If the final volume of the gas is lower than the volume at the start, the temp will be higher than at the start. If the final volume is greater than at the start, then the temp of the gas will be lower than at the start.
Increased heart rate and increased stroke volume
The volume you would expect the gas to occupy if the pressure is increased to 40 kPa would be 50 liters.
The volume of an object is determined by the product of the surface area and the height of the object. Hence if the big container has a bigger height then the volume would certainly be greater. However, when talking about the volume of the liquid, it will be constant. This is because, although the height of the liquid will be reduced by putting it into a bigger container, the surface area is increased. Therefore, it will be constant. ! xx
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.